A flashlight uses Two 3V batteries to provide a steady current of 0.5A in the filament. Find the resistance of the glowing filament? Tell me fast plzzzz .?

Question

Answer

Answer

Total voltage =6v(for both)
I=0.5
from equation,
v=IR
R=V/I....
=6/0.5
=12

Answer

Ohm’s principal discovery was that the amount of electric current through a metal conductor in a circuit is directly proportional to the voltage impressed across it, for any given temperature

V = I x R;

Now in our case;

V = 3V+3V= 6V

I = 0.5 A

R = V/I

R = 6/0.5

R = 12 ohm

Answer

Understanding the Problem:
We are given that a flashlight uses two 3V batteries and provides a steady current of 0.5A in the filament. We need to find the resistance of the glowing filament.

Key Formula:
Ohm's Law: V = I * R
where V is the voltage, I is the current, and R is the resistance.

Step-by-Step Solution:

1. Determine the Voltage:
Since the flashlight uses two 3V batteries, the total voltage supplied to the filament is 3V + 3V = 6V.

2. Determine the Current:
The steady current provided by the flashlight is given as 0.5A.

3. Apply Ohm's Law:
Using Ohm's Law, we can rearrange the formula to solve for resistance:
R = V / I

4. Calculate the Resistance:
Substituting the known values into the formula, we get:
R = 6V / 0.5A
R = 12Ω

Hence, the resistance of the glowing filament in the flashlight is 12Ω.

Summary:
To summarize, the resistance of the glowing filament in the flashlight is found to be 12Ω. This is determined by applying Ohm's Law, which states that the resistance is equal to the voltage divided by the current. By substituting the given values of voltage (6V) and current (0.5A) into the formula, we obtain the final result of 12Ω.

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