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An amount of heat 1000kJ is transferred from a heat reservoir at temperature TA to another heat reservoir at temperature TB . If TA = 800K and and TB = 500K, what is the change in entropy  ΔS of the combined system in JK-1
    Correct answer is '750'. Can you explain this answer?
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    An amount of heat 1000kJ is transferred from a heat reservoir at tempe...
    Conventionally, heat given to the system is taken to be positive and heat extracted from the system is taken to be negative,

    ΔS = ΔSA + ΔS
    B


    ΔS = 750JK-1
    The correct answer is: 750
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    An amount of heat 1000kJ is transferred from a heat reservoir at tempe...
    Calculation of Change in Entropy (ΔS) of the Combined System:
    1. Calculate the Change in Entropy:
    - The change in entropy (ΔS) can be calculated using the formula: ΔS = Q / T, where Q is the heat transferred and T is the temperature.
    2. Calculate the Heat Transferred:
    - The heat transferred (Q) is given as 1000 kJ.
    3. Calculate the Temperatures in Kelvin:
    - The initial temperature (TA) is 800K and the final temperature (TB) is 500K.
    4. Calculate the Change in Entropy:
    - Using the formula, ΔS = Q / T, we get:
    ΔS = 1000 kJ / 800K - 1000 kJ / 500K
    ΔS = 1.25 kJ/K - 2 kJ/K
    ΔS = -0.75 kJ/K
    - Since entropy is a state function, the change in entropy is the sum of the changes of the two reservoirs, so the absolute value of -0.75 kJ/K is taken.
    ΔS = 0.75 kJ/K = 750 J/K
    Therefore, the change in entropy (ΔS) of the combined system is 750 J/K.
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    An amount of heat 1000kJ is transferred from a heat reservoir at temperature TA to another heat reservoir at temperature TB . If TA = 800K and and TB = 500K, what is the change in entropy ΔS of the combined system in JK-1Correct answer is '750'. Can you explain this answer?
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