The efficiency of a heat engine working between heat reservoirs at temperature 327ºC and 27ºC respectively (in percentage) isCorrect answer is '50'. Can you explain this answer?

Question

The efficiency of a heat engine working between heat reservoirs at temperature 327&ordm;C and 27&ordm;C respectively (in percentage) isCorrect answer is '50'. Can you explain this answer?

Answer

Calculation of Efficiency of Heat Engine:

Efficiency of a heat engine is given by the formula:

$$
\eta = 1 - \frac{T_C}{T_H}
$$

where:
- $\eta$ is the efficiency of the heat engine,
- $T_C$ is the temperature of the cold reservoir (27°C = 300K), and
- $T_H$ is the temperature of the hot reservoir (327°C = 600K).

Substitute the values in the formula:

$$
\eta = 1 - \frac{300}{600} = 1 - 0.5 = 0.5 = 50\%
$$

Therefore, the efficiency of the heat engine working between the given heat reservoirs is 50%. This means that the engine is able to convert 50% of the input heat energy into work, while the remaining 50% is expelled as waste heat.

Similar Physics Doubts

A Carnot cycle operates on a working substance between two reservoirs at temperatures T1 and T2 , where, T1 > T2 . Amount of heat Q1 is extracted from the reservoir at T1 and an amount Q2 is delivered to the reservoir at T2. Which of the following statements is incorrect?

A Carnot cycle operates on a working substance between two reservoirs at temperatures T1 and T2 , where, T1 > T2 . Amount of heat Q1 is extracted from the reservoir at T1 and an amount Q2 is delivered to the reservoir at T2. Which of the following statements is incorrect?

Top Courses for Physics

Suggested Free Tests

Related Content

Schools

Competitive Examinations

Quick Access Links

Technical Exams