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(Directions ): Read the following information carefully and answer the questions given beside.
In a certain code language, codes are decided on the basis of following rules and conditions.
Rules:
1. All the consonants that appear before ‘N’ in alphabet series are to be coded as 0-9.(C =1, D= 2 and so on)
2. All the consonants that appear after ‘N’ in alphabet series are to be coded as 0-9.(Q=1, R=2 and so on)
3. ‘N’ is to be coded as 1.
Conditions:
I. If a word starts with a consonant but ends with a vowel then all the vowels of that word are to be coded as ‘#’ and codes for last and first letters will be interchanged.
II. If a word has more than two vowels then the first vowel is to be coded as &, second vowel as *, third vowel as @ and then repeat the codes in the same sequence from fourth vowel onwards.
III. If in a word a consonant that appears after M is either preceded or followed or both by a vowel then all the vowels of that word are to be coded as ‘%’ and 1 is added to the original code of all consonants. (If after adding 1, the original code comes in double digit then add the digits until single digit is obtained.)
IV. If none of the above conditions is applicable in a word then vowels of such word are coded as ‘-‘.
V. If more than one condition is applicable in a single word then apply all the conditions as per the given order.
Q. What is the code for ‘SOLUTION’?
  • a)
    3&8*4@&1
  • b)
    4%9%5%%2
  • c)
    3#8&4@&1
  • d)
    3%8%4%%1
Correct answer is option 'B'. Can you explain this answer?
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(Directions ): Read the following information carefully and answer the questions given beside.In a certain code language, codes are decided on the basis of following rules and conditions.Rules:1. All the consonants that appear before ‘N’ in alphabet series are to be coded as 0-9.(C =1, D= 2 and so on)2. All the consonants that appear after ‘N’ in alphabet series are to be coded as 0-9.(Q=1, R=2 and so on)3. ‘N’ is to be coded as 1.Conditions:I. If a word starts with a consonant but ends with a vowel then all the vowels of that word are to be coded as ‘#’ and codes for last and first letters will be interchanged.II. If a word has more than two vowels then the first vowel is to be coded as &, second vowel as *, third vowel as @ and then repeat the codes in the same sequence from fourth vowel onwards.III. If in a word a consonant that appears after M is either preceded or followed or both by a vowel then all the vowels of that word are to be coded as ‘%’ and 1 is added to the original code of all consonants. (If after adding 1, the original code comes in double digit then add the digits until single digit is obtained.)IV. If none of the above conditions is applicable in a word then vowels of such word are coded as ‘-‘.V. If more than one condition is applicable in a single word then apply all the conditions as per the given order.Q. What is the code for ‘SOLUTION’?a)3&8*4@&1b)4%9%5%%2c)3#8&4@&1d)3%8%4%%1Correct answer is option 'B'. Can you explain this answer?
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(Directions ): Read the following information carefully and answer the questions given beside.In a certain code language, codes are decided on the basis of following rules and conditions.Rules:1. All the consonants that appear before ‘N’ in alphabet series are to be coded as 0-9.(C =1, D= 2 and so on)2. All the consonants that appear after ‘N’ in alphabet series are to be coded as 0-9.(Q=1, R=2 and so on)3. ‘N’ is to be coded as 1.Conditions:I. If a word starts with a consonant but ends with a vowel then all the vowels of that word are to be coded as ‘#’ and codes for last and first letters will be interchanged.II. If a word has more than two vowels then the first vowel is to be coded as &, second vowel as *, third vowel as @ and then repeat the codes in the same sequence from fourth vowel onwards.III. If in a word a consonant that appears after M is either preceded or followed or both by a vowel then all the vowels of that word are to be coded as ‘%’ and 1 is added to the original code of all consonants. (If after adding 1, the original code comes in double digit then add the digits until single digit is obtained.)IV. If none of the above conditions is applicable in a word then vowels of such word are coded as ‘-‘.V. If more than one condition is applicable in a single word then apply all the conditions as per the given order.Q. What is the code for ‘SOLUTION’?a)3&8*4@&1b)4%9%5%%2c)3#8&4@&1d)3%8%4%%1Correct answer is option 'B'. Can you explain this answer? for CLAT 2024 is part of CLAT preparation. The Question and answers have been prepared according to the CLAT exam syllabus. Information about (Directions ): Read the following information carefully and answer the questions given beside.In a certain code language, codes are decided on the basis of following rules and conditions.Rules:1. All the consonants that appear before ‘N’ in alphabet series are to be coded as 0-9.(C =1, D= 2 and so on)2. All the consonants that appear after ‘N’ in alphabet series are to be coded as 0-9.(Q=1, R=2 and so on)3. ‘N’ is to be coded as 1.Conditions:I. If a word starts with a consonant but ends with a vowel then all the vowels of that word are to be coded as ‘#’ and codes for last and first letters will be interchanged.II. If a word has more than two vowels then the first vowel is to be coded as &, second vowel as *, third vowel as @ and then repeat the codes in the same sequence from fourth vowel onwards.III. If in a word a consonant that appears after M is either preceded or followed or both by a vowel then all the vowels of that word are to be coded as ‘%’ and 1 is added to the original code of all consonants. (If after adding 1, the original code comes in double digit then add the digits until single digit is obtained.)IV. If none of the above conditions is applicable in a word then vowels of such word are coded as ‘-‘.V. If more than one condition is applicable in a single word then apply all the conditions as per the given order.Q. What is the code for ‘SOLUTION’?a)3&8*4@&1b)4%9%5%%2c)3#8&4@&1d)3%8%4%%1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for CLAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for (Directions ): Read the following information carefully and answer the questions given beside.In a certain code language, codes are decided on the basis of following rules and conditions.Rules:1. All the consonants that appear before ‘N’ in alphabet series are to be coded as 0-9.(C =1, D= 2 and so on)2. All the consonants that appear after ‘N’ in alphabet series are to be coded as 0-9.(Q=1, R=2 and so on)3. ‘N’ is to be coded as 1.Conditions:I. If a word starts with a consonant but ends with a vowel then all the vowels of that word are to be coded as ‘#’ and codes for last and first letters will be interchanged.II. If a word has more than two vowels then the first vowel is to be coded as &, second vowel as *, third vowel as @ and then repeat the codes in the same sequence from fourth vowel onwards.III. If in a word a consonant that appears after M is either preceded or followed or both by a vowel then all the vowels of that word are to be coded as ‘%’ and 1 is added to the original code of all consonants. (If after adding 1, the original code comes in double digit then add the digits until single digit is obtained.)IV. If none of the above conditions is applicable in a word then vowels of such word are coded as ‘-‘.V. If more than one condition is applicable in a single word then apply all the conditions as per the given order.Q. What is the code for ‘SOLUTION’?a)3&8*4@&1b)4%9%5%%2c)3#8&4@&1d)3%8%4%%1Correct answer is option 'B'. Can you explain this answer?.
Solutions for (Directions ): Read the following information carefully and answer the questions given beside.In a certain code language, codes are decided on the basis of following rules and conditions.Rules:1. All the consonants that appear before ‘N’ in alphabet series are to be coded as 0-9.(C =1, D= 2 and so on)2. All the consonants that appear after ‘N’ in alphabet series are to be coded as 0-9.(Q=1, R=2 and so on)3. ‘N’ is to be coded as 1.Conditions:I. If a word starts with a consonant but ends with a vowel then all the vowels of that word are to be coded as ‘#’ and codes for last and first letters will be interchanged.II. If a word has more than two vowels then the first vowel is to be coded as &, second vowel as *, third vowel as @ and then repeat the codes in the same sequence from fourth vowel onwards.III. If in a word a consonant that appears after M is either preceded or followed or both by a vowel then all the vowels of that word are to be coded as ‘%’ and 1 is added to the original code of all consonants. (If after adding 1, the original code comes in double digit then add the digits until single digit is obtained.)IV. If none of the above conditions is applicable in a word then vowels of such word are coded as ‘-‘.V. If more than one condition is applicable in a single word then apply all the conditions as per the given order.Q. What is the code for ‘SOLUTION’?a)3&8*4@&1b)4%9%5%%2c)3#8&4@&1d)3%8%4%%1Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for CLAT. Download more important topics, notes, lectures and mock test series for CLAT Exam by signing up for free.
Here you can find the meaning of (Directions ): Read the following information carefully and answer the questions given beside.In a certain code language, codes are decided on the basis of following rules and conditions.Rules:1. All the consonants that appear before ‘N’ in alphabet series are to be coded as 0-9.(C =1, D= 2 and so on)2. All the consonants that appear after ‘N’ in alphabet series are to be coded as 0-9.(Q=1, R=2 and so on)3. ‘N’ is to be coded as 1.Conditions:I. If a word starts with a consonant but ends with a vowel then all the vowels of that word are to be coded as ‘#’ and codes for last and first letters will be interchanged.II. If a word has more than two vowels then the first vowel is to be coded as &, second vowel as *, third vowel as @ and then repeat the codes in the same sequence from fourth vowel onwards.III. If in a word a consonant that appears after M is either preceded or followed or both by a vowel then all the vowels of that word are to be coded as ‘%’ and 1 is added to the original code of all consonants. (If after adding 1, the original code comes in double digit then add the digits until single digit is obtained.)IV. If none of the above conditions is applicable in a word then vowels of such word are coded as ‘-‘.V. If more than one condition is applicable in a single word then apply all the conditions as per the given order.Q. What is the code for ‘SOLUTION’?a)3&8*4@&1b)4%9%5%%2c)3#8&4@&1d)3%8%4%%1Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of (Directions ): Read the following information carefully and answer the questions given beside.In a certain code language, codes are decided on the basis of following rules and conditions.Rules:1. All the consonants that appear before ‘N’ in alphabet series are to be coded as 0-9.(C =1, D= 2 and so on)2. All the consonants that appear after ‘N’ in alphabet series are to be coded as 0-9.(Q=1, R=2 and so on)3. ‘N’ is to be coded as 1.Conditions:I. If a word starts with a consonant but ends with a vowel then all the vowels of that word are to be coded as ‘#’ and codes for last and first letters will be interchanged.II. If a word has more than two vowels then the first vowel is to be coded as &, second vowel as *, third vowel as @ and then repeat the codes in the same sequence from fourth vowel onwards.III. If in a word a consonant that appears after M is either preceded or followed or both by a vowel then all the vowels of that word are to be coded as ‘%’ and 1 is added to the original code of all consonants. (If after adding 1, the original code comes in double digit then add the digits until single digit is obtained.)IV. If none of the above conditions is applicable in a word then vowels of such word are coded as ‘-‘.V. If more than one condition is applicable in a single word then apply all the conditions as per the given order.Q. What is the code for ‘SOLUTION’?a)3&8*4@&1b)4%9%5%%2c)3#8&4@&1d)3%8%4%%1Correct answer is option 'B'. Can you explain this answer?, a detailed solution for (Directions ): Read the following information carefully and answer the questions given beside.In a certain code language, codes are decided on the basis of following rules and conditions.Rules:1. All the consonants that appear before ‘N’ in alphabet series are to be coded as 0-9.(C =1, D= 2 and so on)2. All the consonants that appear after ‘N’ in alphabet series are to be coded as 0-9.(Q=1, R=2 and so on)3. ‘N’ is to be coded as 1.Conditions:I. If a word starts with a consonant but ends with a vowel then all the vowels of that word are to be coded as ‘#’ and codes for last and first letters will be interchanged.II. If a word has more than two vowels then the first vowel is to be coded as &, second vowel as *, third vowel as @ and then repeat the codes in the same sequence from fourth vowel onwards.III. If in a word a consonant that appears after M is either preceded or followed or both by a vowel then all the vowels of that word are to be coded as ‘%’ and 1 is added to the original code of all consonants. (If after adding 1, the original code comes in double digit then add the digits until single digit is obtained.)IV. If none of the above conditions is applicable in a word then vowels of such word are coded as ‘-‘.V. If more than one condition is applicable in a single word then apply all the conditions as per the given order.Q. What is the code for ‘SOLUTION’?a)3&8*4@&1b)4%9%5%%2c)3#8&4@&1d)3%8%4%%1Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of (Directions ): Read the following information carefully and answer the questions given beside.In a certain code language, codes are decided on the basis of following rules and conditions.Rules:1. All the consonants that appear before ‘N’ in alphabet series are to be coded as 0-9.(C =1, D= 2 and so on)2. All the consonants that appear after ‘N’ in alphabet series are to be coded as 0-9.(Q=1, R=2 and so on)3. ‘N’ is to be coded as 1.Conditions:I. If a word starts with a consonant but ends with a vowel then all the vowels of that word are to be coded as ‘#’ and codes for last and first letters will be interchanged.II. If a word has more than two vowels then the first vowel is to be coded as &, second vowel as *, third vowel as @ and then repeat the codes in the same sequence from fourth vowel onwards.III. If in a word a consonant that appears after M is either preceded or followed or both by a vowel then all the vowels of that word are to be coded as ‘%’ and 1 is added to the original code of all consonants. (If after adding 1, the original code comes in double digit then add the digits until single digit is obtained.)IV. If none of the above conditions is applicable in a word then vowels of such word are coded as ‘-‘.V. If more than one condition is applicable in a single word then apply all the conditions as per the given order.Q. What is the code for ‘SOLUTION’?a)3&8*4@&1b)4%9%5%%2c)3#8&4@&1d)3%8%4%%1Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice (Directions ): Read the following information carefully and answer the questions given beside.In a certain code language, codes are decided on the basis of following rules and conditions.Rules:1. All the consonants that appear before ‘N’ in alphabet series are to be coded as 0-9.(C =1, D= 2 and so on)2. All the consonants that appear after ‘N’ in alphabet series are to be coded as 0-9.(Q=1, R=2 and so on)3. ‘N’ is to be coded as 1.Conditions:I. If a word starts with a consonant but ends with a vowel then all the vowels of that word are to be coded as ‘#’ and codes for last and first letters will be interchanged.II. If a word has more than two vowels then the first vowel is to be coded as &, second vowel as *, third vowel as @ and then repeat the codes in the same sequence from fourth vowel onwards.III. If in a word a consonant that appears after M is either preceded or followed or both by a vowel then all the vowels of that word are to be coded as ‘%’ and 1 is added to the original code of all consonants. (If after adding 1, the original code comes in double digit then add the digits until single digit is obtained.)IV. If none of the above conditions is applicable in a word then vowels of such word are coded as ‘-‘.V. If more than one condition is applicable in a single word then apply all the conditions as per the given order.Q. What is the code for ‘SOLUTION’?a)3&8*4@&1b)4%9%5%%2c)3#8&4@&1d)3%8%4%%1Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice CLAT tests.
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