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A grating is able to resolve two very close spectral lines of wavelength 5890 A and 5896 A in its first order diffraction. The resolving power of the grating is :
  • a)
    close to 3000
  • b)
    close to 1000
  • c)
    close to 6000
  • d)
    close to 12000
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A grating is able to resolve two very close spectral lines of waveleng...
The two lines will be seen distinctly if they are resolved by grating.
Resolving power

∴ The correct option is close to 1000.
The correct answer is: close to 1000
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Most Upvoted Answer
A grating is able to resolve two very close spectral lines of waveleng...
Concept:
The resolving power of a grating is defined as the ability of the grating to separate two closely spaced spectral lines. It is given by the formula:
Resolving power (R) = N * λ / Δλ
where N is the number of rulings on the grating, λ is the wavelength of light, and Δλ is the difference in wavelengths between the two spectral lines.

Given:
Wavelength of first spectral line (λ1) = 5890 A
Wavelength of second spectral line (λ2) = 5896 A
Order of diffraction (n) = 1

Calculating Resolving Power:
1. Calculate the difference in wavelengths between the two spectral lines:
Δλ = λ2 - λ1 = 5896 A - 5890 A = 6 A

2. Calculate the resolving power using the formula:
R = N * λ / Δλ

3. We know that the order of diffraction (n) for the first order is 1. Hence, the number of rulings on the grating (N) is also 1.

4. Substitute the values into the formula:
R = 1 * λ / Δλ
R = λ / Δλ

5. Convert the wavelengths from Angstroms to meters:
λ = 5890 A * 10^-10 m/A = 5890 * 10^-10 m
Δλ = 6 A * 10^-10 m/A = 6 * 10^-10 m

6. Substitute the values into the formula:
R = (5890 * 10^-10 m) / (6 * 10^-10 m)
R = 5890 / 6

7. Simplify the expression:
R = 981.67

Answer:
The resolving power of the grating is approximately 1000 (close to option 'B').
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A grating is able to resolve two very close spectral lines of wavelength 5890 A and 5896 A in its first order diffraction. The resolving power of the grating is :a)close to 3000b)close to 1000c)close to 6000d)close to 12000Correct answer is option 'B'. Can you explain this answer?
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