An alcohol X (C7H16O) gives immediate turbidity with HCI/ZnCI2 and can...
Introduction:
We are given that the alcohol X (C7H16O) gives immediate turbidity with HCl/ZnCl2 and can be resolved into enantiomers. Additionally, X has a tertiary hydrogen. We need to determine the number of CH3 groups present in X.
Solution:
Step 1: Determine the molecular formula of X
The molecular formula of alcohol X is given as C7H16O. This means that it contains 7 carbon atoms, 16 hydrogen atoms, and 1 oxygen atom.
Step 2: Identify the functional group of alcohol
The functional group of alcohol is -OH, which is attached to a carbon atom.
Step 3: Determine the structure of alcohol X
Since X has a tertiary hydrogen, it means that it has a tertiary carbon atom (a carbon atom bonded to three other carbon atoms). Let's assign the structure of X as follows:
CH3 - CH2 - CH(CH3) - CH2 - CH2 - CH2 - OH
Step 4: Count the number of CH3 groups
From the structure of X, we can see that there are 4 CH3 groups present in X. These CH3 groups are attached to the following carbon atoms:
1. CH3 group attached to the first carbon atom.
2. CH3 group attached to the third carbon atom.
3. CH3 group attached to the fifth carbon atom.
4. CH3 group attached to the sixth carbon atom.
Therefore, alcohol X (C7H16O) contains 4 CH3 groups.
Conclusion:
Alcohol X (C7H16O) contains 4 CH3 groups.