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An organic compound X (C7H16O) on treatm ent with concentrated HCI solution forms immediate turbidity even in the absence of ZnCl2. Also, X is resolvable into enantiomers. The correct statement concerning X isa)It is 3-methy!-2-hexanolb)It turns orange CrO3/H2SO4solution greenc)It is 3-methyl-3-hexanold)It forms yellow precipitate with I2/NaOHCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about An organic compound X (C7H16O) on treatm ent with concentrated HCI solution forms immediate turbidity even in the absence of ZnCl2. Also, X is resolvable into enantiomers. The correct statement concerning X isa)It is 3-methy!-2-hexanolb)It turns orange CrO3/H2SO4solution greenc)It is 3-methyl-3-hexanold)It forms yellow precipitate with I2/NaOHCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An organic compound X (C7H16O) on treatm ent with concentrated HCI solution forms immediate turbidity even in the absence of ZnCl2. Also, X is resolvable into enantiomers. The correct statement concerning X isa)It is 3-methy!-2-hexanolb)It turns orange CrO3/H2SO4solution greenc)It is 3-methyl-3-hexanold)It forms yellow precipitate with I2/NaOHCorrect answer is option 'C'. Can you explain this answer?.

Solutions for An organic compound X (C7H16O) on treatm ent with concentrated HCI solution forms immediate turbidity even in the absence of ZnCl2. Also, X is resolvable into enantiomers. The correct statement concerning X isa)It is 3-methy!-2-hexanolb)It turns orange CrO3/H2SO4solution greenc)It is 3-methyl-3-hexanold)It forms yellow precipitate with I2/NaOHCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.

Here you can find the meaning of An organic compound X (C7H16O) on treatm ent with concentrated HCI solution forms immediate turbidity even in the absence of ZnCl2. Also, X is resolvable into enantiomers. The correct statement concerning X isa)It is 3-methy!-2-hexanolb)It turns orange CrO3/H2SO4solution greenc)It is 3-methyl-3-hexanold)It forms yellow precipitate with I2/NaOHCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of An organic compound X (C7H16O) on treatm ent with concentrated HCI solution forms immediate turbidity even in the absence of ZnCl2. Also, X is resolvable into enantiomers. The correct statement concerning X isa)It is 3-methy!-2-hexanolb)It turns orange CrO3/H2SO4solution greenc)It is 3-methyl-3-hexanold)It forms yellow precipitate with I2/NaOHCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for An organic compound X (C7H16O) on treatm ent with concentrated HCI solution forms immediate turbidity even in the absence of ZnCl2. Also, X is resolvable into enantiomers. The correct statement concerning X isa)It is 3-methy!-2-hexanolb)It turns orange CrO3/H2SO4solution greenc)It is 3-methyl-3-hexanold)It forms yellow precipitate with I2/NaOHCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of An organic compound X (C7H16O) on treatm ent with concentrated HCI solution forms immediate turbidity even in the absence of ZnCl2. Also, X is resolvable into enantiomers. The correct statement concerning X isa)It is 3-methy!-2-hexanolb)It turns orange CrO3/H2SO4solution greenc)It is 3-methyl-3-hexanold)It forms yellow precipitate with I2/NaOHCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice An organic compound X (C7H16O) on treatm ent with concentrated HCI solution forms immediate turbidity even in the absence of ZnCl2. Also, X is resolvable into enantiomers. The correct statement concerning X isa)It is 3-methy!-2-hexanolb)It turns orange CrO3/H2SO4solution greenc)It is 3-methyl-3-hexanold)It forms yellow precipitate with I2/NaOHCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 12 tests.