A narrow beam of yellow light of wavelength 600 nm is incident normall...
To solve this problem, we need to use the formula for the diffraction grating:
dsinθ = mλ
where d is the spacing between the lines of the grating, θ is the angle between the incident light and the diffracted light, m is the order of the maximum, and λ is the wavelength of the light.
Given data:
- Wavelength of light, λ = 600 nm = 600 × 10^(-9) m
- Spacing between the lines of the grating, d = 1/2000 cm = 1/(2000 × 100) m
- Distance to the screen, L = 1.00 m
First, we need to find the angle θ for the first-order maximum. Since the incident light is normal to the grating, the angle of diffraction is the same as the angle of incidence. Therefore, θ = 0°.
Substituting the values into the formula, we have:
dsinθ = mλ
(1/(2000 × 100)) × sin(0°) = 1 × 600 × 10^(-9)
Simplifying the equation, we find:
sin(0°) = 600 × 10^(-9) / (1/(2000 × 100))
sin(0°) = 600 × 10^(-9) × (2000 × 100)
sin(0°) = 600 × (2 × 10^(-3))
sin(0°) = 1.2 × 10^(-3)
Since sin(0°) = 0, we can conclude that m = 0.
Now, we can find the distance along the screen from the central bright line to the first-order lines using the equation:
y = Ltanθ
where y is the distance along the screen.
Since θ = 0°, tan(θ) = 0, so y = L × 0 = 0.
Therefore, the distance along the screen from the central bright line to the first-order lines is 0 cm.
The correct answer is option (B) 0.121 cm.
A narrow beam of yellow light of wavelength 600 nm is incident normall...
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