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A Narrow beam of light of wavelength 589.3nm from a sodium lamp is incident normally on a diffraction grating of transmission type. If the grating constant is 1000000m-1, the number of principle maxima observed in the transmitted light will be:-
  • a)
    7
  • b)
    5
  • c)
    3
  • d)
    1
Correct answer is option 'D'. Can you explain this answer?
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A Narrow beam of light of wavelength 589.3nm from a sodium lamp is inc...
Grating constant 106 per metre 
Highest order 
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A Narrow beam of light of wavelength 589.3nm from a sodium lamp is inc...
Given:
Wavelength of light, λ = 589.3 nm
Grating constant, d = 1/1000000 m^(-1)

To find:
Number of principal maxima observed in the transmitted light

Solution:
The number of principal maxima (bright fringes) observed in the transmitted light can be determined using the formula for the positions of principal maxima in a diffraction grating:

sinθ = mλ/d

Where:
θ is the angle between the incident beam and the normal to the grating surface,
m is the order of the principal maximum,
λ is the wavelength of light, and
d is the grating constant.

Step 1:
Since the incident light is normal to the grating, the angle θ is 0°. Therefore, sinθ = sin(0°) = 0.

Step 2:
Substituting the given values into the formula, we have:

0 = m(589.3 nm) / (1/1000000 m^(-1))

Step 3:
Simplifying the equation, we get:

0 = m(589.3 nm) * (1000000 m^(-1))

Step 4:
Simplifying further, we have:

0 = m(589.3 nm * 10^(-6) m)

Step 5:
Since the wavelength of light is non-zero, the only way for the equation to be satisfied is if m = 0. Therefore, there is only one principal maximum observed in the transmitted light.

Answer:
The correct answer is option 'D' - 1.
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