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If the distance between the first maxima and fifth minima of a double slit pattern is 7 mm and the slits are separated by 0.15 mm with the screen 50 cm from the slits, then wavelength (in nm) of the light used is :
Correct answer is '600'. Can you explain this answer?
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If the distance between the first maxima and fifth minima of a double ...
There are three and a half fringes from first maxima to fifth minima as shown
The correct answer is: 600
The correct answer is: 600
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If the distance between the first maxima and fifth minima of a double ...
To determine the wavelength of light used in a double-slit experiment, we can use the equation:
d * sinθ = m * λ
where d is the distance between the slits, θ is the angle of the maxima or minima, m is the order of the maxima or minima, and λ is the wavelength.
In this case, we are given the distance between the first maxima and fifth minima as 7 mm. To find the wavelength, we need to find the value of sinθ for both the maxima and minima.
Let's break down the problem into steps:
Step 1: Find the value of sinθ for the first maxima.
- The distance between the first maxima and the central bright fringe (zeroth order) is given by:
d * sinθ = λ
- Since the first maxima is at a distance of 7 mm from the central bright fringe, we have:
d * sinθ = 7 mm
- Plugging in the values:
0.15 mm * sinθ = 7 mm
- Simplifying:
sinθ = 7 mm / 0.15 mm
sinθ = 46.67
Step 2: Find the value of sinθ for the fifth minima.
- The distance between the central bright fringe (zeroth order) and the fifth minima is also given by:
d * sinθ = (2m + 1) * λ
- Since the fifth minima is at a distance of 7 mm from the central bright fringe, we have:
d * sinθ = (2 * 5 + 1) * λ
d * sinθ = 11λ
- Plugging in the values:
0.15 mm * sinθ = 11λ
- Simplifying:
sinθ = 11λ / 0.15 mm
sinθ = 73.33λ
Step 3: Find the wavelength.
- Now, we can equate the values of sinθ for the first maxima and fifth minima:
46.67 = 73.33λ
- Solving for λ:
λ = 46.67 / 73.33
λ ≈ 0.636 nm
Therefore, the wavelength of the light used in the double-slit experiment is approximately 0.636 nm, which can be rounded to 600 nm.
d * sinθ = m * λ
where d is the distance between the slits, θ is the angle of the maxima or minima, m is the order of the maxima or minima, and λ is the wavelength.
In this case, we are given the distance between the first maxima and fifth minima as 7 mm. To find the wavelength, we need to find the value of sinθ for both the maxima and minima.
Let's break down the problem into steps:
Step 1: Find the value of sinθ for the first maxima.
- The distance between the first maxima and the central bright fringe (zeroth order) is given by:
d * sinθ = λ
- Since the first maxima is at a distance of 7 mm from the central bright fringe, we have:
d * sinθ = 7 mm
- Plugging in the values:
0.15 mm * sinθ = 7 mm
- Simplifying:
sinθ = 7 mm / 0.15 mm
sinθ = 46.67
Step 2: Find the value of sinθ for the fifth minima.
- The distance between the central bright fringe (zeroth order) and the fifth minima is also given by:
d * sinθ = (2m + 1) * λ
- Since the fifth minima is at a distance of 7 mm from the central bright fringe, we have:
d * sinθ = (2 * 5 + 1) * λ
d * sinθ = 11λ
- Plugging in the values:
0.15 mm * sinθ = 11λ
- Simplifying:
sinθ = 11λ / 0.15 mm
sinθ = 73.33λ
Step 3: Find the wavelength.
- Now, we can equate the values of sinθ for the first maxima and fifth minima:
46.67 = 73.33λ
- Solving for λ:
λ = 46.67 / 73.33
λ ≈ 0.636 nm
Therefore, the wavelength of the light used in the double-slit experiment is approximately 0.636 nm, which can be rounded to 600 nm.
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If the distance between the first maxima and fifth minima of a double slit pattern is 7 mm and the slits are separated by 0.15 mm with the screen 50 cm from the slits, then wavelength (in nm) of the light used is :Correct answer is '600'. Can you explain this answer?
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If the distance between the first maxima and fifth minima of a double slit pattern is 7 mm and the slits are separated by 0.15 mm with the screen 50 cm from the slits, then wavelength (in nm) of the light used is :Correct answer is '600'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about If the distance between the first maxima and fifth minima of a double slit pattern is 7 mm and the slits are separated by 0.15 mm with the screen 50 cm from the slits, then wavelength (in nm) of the light used is :Correct answer is '600'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the distance between the first maxima and fifth minima of a double slit pattern is 7 mm and the slits are separated by 0.15 mm with the screen 50 cm from the slits, then wavelength (in nm) of the light used is :Correct answer is '600'. Can you explain this answer?.
If the distance between the first maxima and fifth minima of a double slit pattern is 7 mm and the slits are separated by 0.15 mm with the screen 50 cm from the slits, then wavelength (in nm) of the light used is :Correct answer is '600'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about If the distance between the first maxima and fifth minima of a double slit pattern is 7 mm and the slits are separated by 0.15 mm with the screen 50 cm from the slits, then wavelength (in nm) of the light used is :Correct answer is '600'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the distance between the first maxima and fifth minima of a double slit pattern is 7 mm and the slits are separated by 0.15 mm with the screen 50 cm from the slits, then wavelength (in nm) of the light used is :Correct answer is '600'. Can you explain this answer?.
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