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The contents of accumulator after the execution of following instruction will be
MVI A, A7H
ORA A
RLC
ORA A
RLC
- a)CFH
- b)4FH
- c)4EH
- d)CEH
Correct answer is option 'B'. Can you explain this answer?
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The contents of accumulator after the execution of following instructi...
The contents of bit D7 are placed in bit D0
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The contents of accumulator after the execution of following instructi...
Explanation:
The given instruction is MVI A, A7H followed by ORA A and RLC instructions. Let's break down the execution of each instruction and determine the final value in the accumulator.
MVI A, A7H:
- This instruction is used to move the immediate value A7H into the accumulator.
- The accumulator is now loaded with A7H.
ORA A:
- This instruction performs a logical OR operation between the accumulator (A) and itself.
- The OR operation is a bitwise operation that sets each bit in the result to 1 if the corresponding bits in either operand are 1.
- Since the accumulator is ORed with itself, all the bits remain unchanged.
- The accumulator value is still A7H.
RLC:
- This instruction performs a rotate left through carry operation on the accumulator.
- The rotate left operation shifts all the bits in the accumulator one position to the left, and the leftmost bit is moved to the carry flag (CF).
- The carry flag is then shifted into the rightmost bit of the accumulator.
- After the RLC operation, the accumulator value becomes 4FH.
Final Result:
- After the execution of the given instructions, the accumulator contains the value 4FH.
Therefore, the correct answer is option 'B' - 4FH.
The given instruction is MVI A, A7H followed by ORA A and RLC instructions. Let's break down the execution of each instruction and determine the final value in the accumulator.
MVI A, A7H:
- This instruction is used to move the immediate value A7H into the accumulator.
- The accumulator is now loaded with A7H.
ORA A:
- This instruction performs a logical OR operation between the accumulator (A) and itself.
- The OR operation is a bitwise operation that sets each bit in the result to 1 if the corresponding bits in either operand are 1.
- Since the accumulator is ORed with itself, all the bits remain unchanged.
- The accumulator value is still A7H.
RLC:
- This instruction performs a rotate left through carry operation on the accumulator.
- The rotate left operation shifts all the bits in the accumulator one position to the left, and the leftmost bit is moved to the carry flag (CF).
- The carry flag is then shifted into the rightmost bit of the accumulator.
- After the RLC operation, the accumulator value becomes 4FH.
Final Result:
- After the execution of the given instructions, the accumulator contains the value 4FH.
Therefore, the correct answer is option 'B' - 4FH.
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The contents of accumulator after the execution of following instruction will beMVI A, A7HORA ARLCa)CFHb)4FHc)4EHd)CEHCorrect answer is option 'B'. Can you explain this answer?
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