Electronics and Communication Engineering (ECE) Exam > Electronics and Communication Engineering (ECE) Questions > Consider the following programMVI A,BYTE1RR...
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Consider the following program
MVI A,BYTE1
RRC
RRC
RRC
RRC
If BYTE1 = 32H, the contents of A after the execution of program will be
- a)08H
- b)8CH
- c)12H
- d)None of the above
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Consider the following programMVI A,BYTE1RRCRRCIf BYTE1 = 32H, the c...
Contents of Accumulator A = 0011 0010
After First RRC = 0001 1001
After second RRC = 1000 1100
After second RRC = 1000 1100
Most Upvoted Answer
Consider the following programMVI A,BYTE1RRCRRCIf BYTE1 = 32H, the c...
Explanation:
The given program performs two right circular shifts (RRC) on the content of register A.
Initial State:
A = BYTE1 = 32H (00110010 in binary)
First RRC:
After the first RRC, the content of A will shift right by one bit. The rightmost bit will be shifted to the leftmost position.
A = 16H (00010000 in binary)
Second RRC:
After the second RRC, the content of A will shift right by one bit again.
A = 08H (00001000 in binary)
Final State:
After the execution of the program, the content of A will be 08H.
Therefore, the correct answer is option 'B' (8CH).
The given program performs two right circular shifts (RRC) on the content of register A.
Initial State:
A = BYTE1 = 32H (00110010 in binary)
First RRC:
After the first RRC, the content of A will shift right by one bit. The rightmost bit will be shifted to the leftmost position.
A = 16H (00010000 in binary)
Second RRC:
After the second RRC, the content of A will shift right by one bit again.
A = 08H (00001000 in binary)
Final State:
After the execution of the program, the content of A will be 08H.
Therefore, the correct answer is option 'B' (8CH).
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Consider the following programMVI A,BYTE1RRCRRCIf BYTE1 = 32H, the contents of A after the execution of program will bea)08Hb)8CHc)12Hd)None of the aboveCorrect answer is option 'B'. Can you explain this answer?
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