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If one of the roots of the quadratic equation x2 + bx + 98 = 0 is the average (arithmetic mean) of the  roots of the equation x2 + 28x – 588 = 0, what is the other root of the equation x2 + bx + 98 = 0?
  • a)
    -7
  • b)
    −5/2
  • c)
    5/2
  • d)
    7
  • e)
    21
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
If one of the roots of the quadratic equation x2 + bx + 98 = 0 is the ...
Given
To Find: value of n?
Approach
  1. We know that the product of roots m and n is equal to c/a
  1. So, we can write m*n = 98, i.e. n = 98/m
  2. So, for finding n, we need to find m
  • We are given that m = (p+q)/2
  1. We know that sum of roots of the quadratic equation is −b/a
  2. We will use this relation to find the value of p + q and hence the value of m
Hence, the other root of the equation x2 + bx + 98 = 0 is -7
Answer: A
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Most Upvoted Answer
If one of the roots of the quadratic equation x2 + bx + 98 = 0 is the ...
Problem Analysis:
We are given two quadratic equations: x^2 + bx + 98 = 0 and x^2 + 28x + 588 = 0. We need to find the other root of the equation x^2 + bx + 98 = 0, given that one of the roots is the average of the roots of the equation x^2 + 28x + 588 = 0.

Key Observations:
Let's denote the roots of x^2 + 28x + 588 = 0 as α and β.
The sum of the roots, α + β, can be found using the formula: α + β = -b/a.
The product of the roots, α * β, can be found using the formula: α * β = c/a.

Solution:
1. Find the sum and product of the roots of x^2 + 28x + 588 = 0:
- Using the formula α + β = -b/a, we find: α + β = -28/1 = -28.
- Using the formula α * β = c/a, we find: α * β = 588/1 = 588.

2. Find the average of the roots of x^2 + 28x + 588 = 0:
- The average of the roots is (α + β)/2 = (-28)/2 = -14.

3. Set up the equation for the other root of x^2 + bx + 98 = 0:
- We know that one of the roots is -14.
- Let the other root be r.
- The sum of the roots is -14 + r = -b/a.
- The product of the roots is -14 * r = 98/a.

4. Solve the equation to find r:
- Rearrange the equation -14 + r = -b/a to get r = -14 - b/a.
- Substitute the value of α * β = 98/a from step 3: -14 * r = 98/a.
- Simplify: -14r = 98/a.
- Multiply both sides by -a/14: r = -98/14 = -7.

5. Answer:
- The other root of the equation x^2 + bx + 98 = 0 is -7.
- Therefore, the correct answer is option A.
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If one of the roots of the quadratic equation x2 + bx + 98 = 0 is the average (arithmetic mean) of the roots of the equation x2 + 28x – 588 = 0, what is the other root of the equation x2 + bx + 98 = 0?a)-7b)−5/2c)5/2d)7e)21Correct answer is option 'A'. Can you explain this answer?
Question Description
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