The potential energy of a particle executing S.H.M. is 2.5 J when its ...
Total energy
Potential energy
So total energy
The correct answer is: 10
View all questions of this test
The potential energy of a particle executing S.H.M. is 2.5 J when its ...
The potential energy of a particle executing simple harmonic motion (S.H.M.) can be calculated using the formula:
Potential Energy = (1/2) * k * x²
Where:
- k is the spring constant (a measure of the stiffness of the spring)
- x is the displacement of the particle from its equilibrium position
In this case, we are given that the potential energy of the particle is 2.5 J when its displacement is half of the amplitude.
Let's assume that the amplitude of the S.H.M. is A. Therefore, when the displacement is half of the amplitude, it is A/2.
Using the given information, we can set up the equation:
2.5 = (1/2) * k * (A/2)²
Simplifying the equation:
2.5 = (1/2) * k * (A²/4)
Multiplying both sides by 4 to eliminate the fraction:
10 = k * (A²/4)
Multiplying both sides by 4/A²:
40/A² = k
Now, the total energy of the particle in S.H.M. is the sum of its kinetic energy and potential energy. Since total energy remains constant throughout the motion, it is equal to the maximum potential energy.
The maximum potential energy is given by:
Potential Energy = (1/2) * k * A²
Substituting the value of k from the previous equation:
Potential Energy = (1/2) * (40/A²) * A²
Simplifying the equation:
Potential Energy = 20
Therefore, the total energy of the particle is 20 J.