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A particle is executing SHM with an amplitude 4 cm. The displacement (in cm) at which its energy it half kinetic and half potential is :
    Correct answer is '2.828'. Can you explain this answer?
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    A particle is executing SHM with an amplitude 4 cm. The displacement (...

    Potential energy = Kinetic energy

    The correct answer is: 2.828
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    A particle is executing SHM with an amplitude 4 cm. The displacement (...
    Given:
    - Amplitude of SHM = 4 cm

    To find:
    - Displacement at which the energy is half kinetic and half potential

    Explanation:
    1. Understanding Simple Harmonic Motion (SHM):
    - Simple Harmonic Motion (SHM) is a type of periodic motion in which the restoring force is directly proportional to the displacement of the particle from its equilibrium position.
    - The displacement of the particle from its equilibrium position is given by the equation:
    x = A*cos(ωt + φ)
    where x is the displacement, A is the amplitude, ω is the angular frequency, t is the time, and φ is the phase constant.

    2. Energy in SHM:
    - The total mechanical energy of a particle executing SHM is the sum of its kinetic energy and potential energy.
    - The kinetic energy (KE) of the particle is given by the equation:
    KE = 1/2 * m * v^2
    where m is the mass of the particle and v is its velocity.
    - The potential energy (PE) of the particle is given by the equation:
    PE = 1/2 * k * x^2
    where k is the spring constant and x is the displacement of the particle.

    3. Finding the Displacement:
    - The total mechanical energy (E) of the particle is constant throughout the motion and is given by:
    E = KE + PE
    - Since the energy is half kinetic and half potential, we can write:
    KE = 1/2 * E
    PE = 1/2 * E
    - Substituting the equations for KE and PE, we get:
    1/2 * m * v^2 = 1/2 * E
    1/2 * k * x^2 = 1/2 * E
    - Rearranging the equations, we find:
    v^2 = E/m
    x^2 = E/k
    - Since E is constant, we can write:
    v^2 = x^2 * k/m
    - Using the equation for velocity in SHM, we have:
    v = -A * ω * sin(ωt + φ)
    - Substituting this equation into the previous equation, we get:
    (-A * ω * sin(ωt + φ))^2 = x^2 * k/m
    - Simplifying the equation, we find:
    A^2 * ω^2 * sin^2(ωt + φ) = x^2 * k/m
    - Since the amplitude is given, we can write:
    4^2 * ω^2 * sin^2(ωt + φ) = x^2 * k/m
    16 * ω^2 * sin^2(ωt + φ) = x^2 * k/m
    - The maximum value of sin^2(ωt + φ) is 1, so we can write:
    16 * ω^2 = x^2 * k/m
    - Rearranging the equation, we find:
    x^2 = 16 * ω^2 * m/k
    - Substituting the value of ω^2 (ω^2 = k/m),
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    A particle is executing SHM with an amplitude 4 cm. The displacement (...
    2.82842
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    A particle is executing SHM with an amplitude 4 cm. The displacement (in cm) at which its energy it half kinetic and half potential is :Correct answer is '2.828'. Can you explain this answer?
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