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A particle is executing simple harmonic motion (SHM) of amplitude A, along the x-axis, about x = 0. When its potential energy (PE) equals kinetic energy (KE), the position of the particle will be
  • a)
     A/2
  • b)
     A/2√2
  • c)
     A/√2
  • d)
    A
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A particle is executing simple harmonic motion (SHM) of amplitude A, a...
Potential energy (U) = (½)kx2
Kinetic energy (K) = (½)kA2 – (½)kx2
Given, U = K
(½)kx= (½)kA2 – (½)kx
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A particle is executing simple harmonic motion (SHM) of amplitude A, along the x-axis, about x = 0. When its potential energy (PE) equals kinetic energy (KE), the position of the particle will bea)A/2b)A/2√2c)A/√2d)ACorrect answer is option 'C'. Can you explain this answer?
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