The area bounded byy= 1 + 2sin2x,xandndash; axis,x= 0and x =andpi; is :a)8andpi; sq. unitsb)4andpi;sq. unitsc)6andpi;sq. unitsd)2andpi;sq. unitsCorrect answer is option 'D'. Can you explain this answer?

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The area bounded by y = 1 + 2sin²x, x – axis, x = 0 and x = π is :

a)
8π sq. units
b)
4π sq. units
c)
6π sq. units
d)
2π sq. units

Correct answer is option 'D'. Can you explain this answer?

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The area bounded byy= 1 + 2sin2x,x– axis,x= 0and x =π is :a)8...

For x ∈ (0, π) y = 1 + sin²x is a non negative, function.
∴ The area bounded. by y = 1 + 2sin²x, x-axis, x = 0 and x = π will be in first quadrant.
∴ The area required

The correct answer is: 2π sq. units

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The area bounded byy= 1 + 2sin2x,x– axis,x= 0and x =π is :a)8π sq. unitsb)4πsq. unitsc)6πsq. unitsd)2πsq. unitsCorrect answer is option 'D'. Can you explain this answer?

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