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In an air-filled rectangular waveguide the cutoff frequencies for TM11 and TE03 modes are both equal to 12 GHz.
Que: The dominant mode is
- a)TM10
- b)TM01
- c)TE01
- d)TE10
Correct answer is option 'C'. Can you explain this answer?
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In an air-filled rectangular waveguide the cutoff frequencies for TM11...
Most Upvoted Answer
In an air-filled rectangular waveguide the cutoff frequencies for TM11...
Explanation:
- A rectangular waveguide is a type of waveguide that is used to transmit electromagnetic waves in microwave frequency range.
- TM11 and TE03 are the modes of propagation in a rectangular waveguide.
- The cutoff frequency for a mode of propagation is the lowest frequency at which that mode can propagate without attenuation.
- In this case, the cutoff frequency for both TM11 and TE03 modes is 12 GHz.
- The dominant mode is the mode with the lowest cutoff frequency, which means it can propagate at lower frequencies than any other mode.
- Therefore, the dominant mode in this case is TE01, which has a cutoff frequency of 0 GHz (i.e., it can propagate at DC).
- TM10 and TM01 modes have cutoff frequencies higher than 12 GHz, so they cannot propagate in this waveguide below 12 GHz.
- TE10 mode has a cutoff frequency of 8.42 GHz, which is higher than 12 GHz, so it cannot propagate in this waveguide below 12 GHz.
Therefore, the correct answer is option 'C' (TE01).
- A rectangular waveguide is a type of waveguide that is used to transmit electromagnetic waves in microwave frequency range.
- TM11 and TE03 are the modes of propagation in a rectangular waveguide.
- The cutoff frequency for a mode of propagation is the lowest frequency at which that mode can propagate without attenuation.
- In this case, the cutoff frequency for both TM11 and TE03 modes is 12 GHz.
- The dominant mode is the mode with the lowest cutoff frequency, which means it can propagate at lower frequencies than any other mode.
- Therefore, the dominant mode in this case is TE01, which has a cutoff frequency of 0 GHz (i.e., it can propagate at DC).
- TM10 and TM01 modes have cutoff frequencies higher than 12 GHz, so they cannot propagate in this waveguide below 12 GHz.
- TE10 mode has a cutoff frequency of 8.42 GHz, which is higher than 12 GHz, so it cannot propagate in this waveguide below 12 GHz.
Therefore, the correct answer is option 'C' (TE01).
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Community Answer
In an air-filled rectangular waveguide the cutoff frequencies for TM11...
If you solve for a and b values using cutoff frequency formula, you will get b>a so TE 01 is dominant mode.
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In an air-filled rectangular waveguide the cutoff frequencies for TM11 and TE03 modes are both equal to 12 GHz.Que: The dominant mode isa)TM10b)TM01c)TE01d)TE10Correct answer is option 'C'. Can you explain this answer?
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