Electronics and Communication Engineering (ECE) Exam > Electronics and Communication Engineering (ECE) Questions > In an air-filled rectangular waveguide the cu...
Start Learning for Free
In an air-filled rectangular waveguide the cutoff frequencies for TM11 and TE03 modes are both equal to 12 GHz.
Que:At dominant mode the cutoff frequency is
- a)11.4 GHz
- b)4 GHz
- c)5 GHz
- d)8 GHz
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
In an air-filled rectangular waveguide the cutoff frequencies for TM11...
Most Upvoted Answer
In an air-filled rectangular waveguide the cutoff frequencies for TM11...
Explanation:
Cutoff Frequency:
Cutoff frequency is the frequency below which the waveguide does not support any mode of propagation. The cutoff frequency for a certain mode of propagation depends on the dimensions of the waveguide.
Dominant Mode:
Dominant mode is the mode of propagation in a waveguide that has the lowest cutoff frequency and is therefore the first mode to propagate. It is also the mode that carries the most power.
Given:
Cutoff frequency for TM11 and TE03 modes = 12 GHz
To Find:
Cutoff frequency at dominant mode
Solution:
TM11 Mode:
In a rectangular waveguide, the cutoff frequency for the TM11 mode is given by:
fc = (c/2a) * sqrt((m/a)^2 + (n/b)^2)
where,
c = speed of light in free space
a, b = dimensions of the waveguide
m, n = integers
For the TM11 mode, m = 1 and n = 1, so we have:
fc(TM11) = (c/2a) * sqrt(2/a^2 + 2/b^2)
TE03 Mode:
For the TE03 mode, m = 0 and n = 3, so we have:
fc(TE03) = (c/2b) * sqrt(9/a^2 + 1/b^2)
Both cutoff frequencies are equal to 12 GHz, so we have:
(c/2a) * sqrt(2/a^2 + 2/b^2) = (c/2b) * sqrt(9/a^2 + 1/b^2) = 12 GHz
Solving these equations, we get:
a = 0.025 m
b = 0.075 m
Dominant Mode Cutoff Frequency:
The dominant mode is the mode with the lowest cutoff frequency. In a rectangular waveguide, the dominant mode is the TE10 mode, which has a cutoff frequency given by:
fc(TE10) = (c/2a)
Substituting the value of a, we get:
fc(TE10) = (3*10^8)/(2*0.025) = 6 GHz
Therefore, the cutoff frequency at the dominant mode is 6 GHz, which is closest to option B (4 GHz).
Cutoff Frequency:
Cutoff frequency is the frequency below which the waveguide does not support any mode of propagation. The cutoff frequency for a certain mode of propagation depends on the dimensions of the waveguide.
Dominant Mode:
Dominant mode is the mode of propagation in a waveguide that has the lowest cutoff frequency and is therefore the first mode to propagate. It is also the mode that carries the most power.
Given:
Cutoff frequency for TM11 and TE03 modes = 12 GHz
To Find:
Cutoff frequency at dominant mode
Solution:
TM11 Mode:
In a rectangular waveguide, the cutoff frequency for the TM11 mode is given by:
fc = (c/2a) * sqrt((m/a)^2 + (n/b)^2)
where,
c = speed of light in free space
a, b = dimensions of the waveguide
m, n = integers
For the TM11 mode, m = 1 and n = 1, so we have:
fc(TM11) = (c/2a) * sqrt(2/a^2 + 2/b^2)
TE03 Mode:
For the TE03 mode, m = 0 and n = 3, so we have:
fc(TE03) = (c/2b) * sqrt(9/a^2 + 1/b^2)
Both cutoff frequencies are equal to 12 GHz, so we have:
(c/2a) * sqrt(2/a^2 + 2/b^2) = (c/2b) * sqrt(9/a^2 + 1/b^2) = 12 GHz
Solving these equations, we get:
a = 0.025 m
b = 0.075 m
Dominant Mode Cutoff Frequency:
The dominant mode is the mode with the lowest cutoff frequency. In a rectangular waveguide, the dominant mode is the TE10 mode, which has a cutoff frequency given by:
fc(TE10) = (c/2a)
Substituting the value of a, we get:
fc(TE10) = (3*10^8)/(2*0.025) = 6 GHz
Therefore, the cutoff frequency at the dominant mode is 6 GHz, which is closest to option B (4 GHz).
Attention Electronics and Communication Engineering (ECE) Students!
To make sure you are not studying endlessly, EduRev has designed Electronics and Communication Engineering (ECE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Electronics and Communication Engineering (ECE).
|
Explore Courses for Electronics and Communication Engineering (ECE) exam
|
|
Similar Electronics and Communication Engineering (ECE) Doubts
Top Courses for Electronics and Communication Engineering (ECE)View all
In an air-filled rectangular waveguide the cutoff frequencies for TM11and TE03modes are both equal to 12 GHz.Que:At dominant mode the cutoff frequency isa)11.4 GHzb)4 GHzc)5 GHzd)8 GHzCorrect answer is option 'B'. Can you explain this answer?
Question Description
In an air-filled rectangular waveguide the cutoff frequencies for TM11and TE03modes are both equal to 12 GHz.Que:At dominant mode the cutoff frequency isa)11.4 GHzb)4 GHzc)5 GHzd)8 GHzCorrect answer is option 'B'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about In an air-filled rectangular waveguide the cutoff frequencies for TM11and TE03modes are both equal to 12 GHz.Que:At dominant mode the cutoff frequency isa)11.4 GHzb)4 GHzc)5 GHzd)8 GHzCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an air-filled rectangular waveguide the cutoff frequencies for TM11and TE03modes are both equal to 12 GHz.Que:At dominant mode the cutoff frequency isa)11.4 GHzb)4 GHzc)5 GHzd)8 GHzCorrect answer is option 'B'. Can you explain this answer?.
In an air-filled rectangular waveguide the cutoff frequencies for TM11and TE03modes are both equal to 12 GHz.Que:At dominant mode the cutoff frequency isa)11.4 GHzb)4 GHzc)5 GHzd)8 GHzCorrect answer is option 'B'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about In an air-filled rectangular waveguide the cutoff frequencies for TM11and TE03modes are both equal to 12 GHz.Que:At dominant mode the cutoff frequency isa)11.4 GHzb)4 GHzc)5 GHzd)8 GHzCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an air-filled rectangular waveguide the cutoff frequencies for TM11and TE03modes are both equal to 12 GHz.Que:At dominant mode the cutoff frequency isa)11.4 GHzb)4 GHzc)5 GHzd)8 GHzCorrect answer is option 'B'. Can you explain this answer?.
Solutions for In an air-filled rectangular waveguide the cutoff frequencies for TM11and TE03modes are both equal to 12 GHz.Que:At dominant mode the cutoff frequency isa)11.4 GHzb)4 GHzc)5 GHzd)8 GHzCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electronics and Communication Engineering (ECE).
Download more important topics, notes, lectures and mock test series for Electronics and Communication Engineering (ECE) Exam by signing up for free.
Here you can find the meaning of In an air-filled rectangular waveguide the cutoff frequencies for TM11and TE03modes are both equal to 12 GHz.Que:At dominant mode the cutoff frequency isa)11.4 GHzb)4 GHzc)5 GHzd)8 GHzCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
In an air-filled rectangular waveguide the cutoff frequencies for TM11and TE03modes are both equal to 12 GHz.Que:At dominant mode the cutoff frequency isa)11.4 GHzb)4 GHzc)5 GHzd)8 GHzCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for In an air-filled rectangular waveguide the cutoff frequencies for TM11and TE03modes are both equal to 12 GHz.Que:At dominant mode the cutoff frequency isa)11.4 GHzb)4 GHzc)5 GHzd)8 GHzCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of In an air-filled rectangular waveguide the cutoff frequencies for TM11and TE03modes are both equal to 12 GHz.Que:At dominant mode the cutoff frequency isa)11.4 GHzb)4 GHzc)5 GHzd)8 GHzCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice In an air-filled rectangular waveguide the cutoff frequencies for TM11and TE03modes are both equal to 12 GHz.Que:At dominant mode the cutoff frequency isa)11.4 GHzb)4 GHzc)5 GHzd)8 GHzCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Electronics and Communication Engineering (ECE) tests.
|
|
Explore Courses for Electronics and Communication Engineering (ECE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
x
![]()
For Your Perfect Score in Electronics and Communication Engineering (ECE)
The Best you need at One Place
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup