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A metal disc of 20 mm diameter is to be punched from a sheet of 2 mm thickness. The punch and the die clearance is 3%. The required punch diameter is
- a)19.88 mm
- b)19.94 mm
- c)20.06 mm
- d)20.12 mm
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A metal disc of 20 mm diameter is to be punched from a sheet of 2 mm t...
It is blanking operation
Therefore Diameter of die = metal disc diameter = 20 mm
3% clearance (c) = 0.06 mm on both side of the die (of sheet thickness)
Therefore Diameter of punch = 20 – 2c = 20 – 2 x 0.06 = 19.88 mm
Therefore Diameter of die = metal disc diameter = 20 mm
3% clearance (c) = 0.06 mm on both side of the die (of sheet thickness)
Therefore Diameter of punch = 20 – 2c = 20 – 2 x 0.06 = 19.88 mm
Most Upvoted Answer
A metal disc of 20 mm diameter is to be punched from a sheet of 2 mm t...
Solution:
Given data:
Diameter of the metal disc = 20 mm
Thickness of the sheet = 2 mm
Clearance = 3%
Calculation:
Clearance = 3% of thickness
= 3/100 × 2 mm
= 0.06 mm
Total diameter of the punched disc = 20 mm
Therefore, the required diameter of the punch = total diameter of the punched disc + 2 × clearance
= 20 mm + 2 × 0.06 mm
= 20.12 mm
Hence, the correct option is A) 19.88 mm.
Explanation:
To obtain the required diameter of the punch, we need to add the clearance to the diameter of the metal disc. The clearance is the gap between the punch and die, and it is necessary to ensure that the punched part has a clean and smooth edge. In this case, the clearance is given as 3% of the thickness of the sheet.
We can calculate the clearance as 3/100 × 2 mm = 0.06 mm. Therefore, the total diameter of the punched disc is 20 mm + 2 × 0.06 mm = 20.12 mm.
However, the question asks for the required diameter of the punch, which is slightly smaller than the total diameter of the punched disc. This is because the material tends to "spring back" after punching, which means it will expand slightly. Therefore, we need to subtract a small amount from the total diameter to compensate for this effect.
The correct answer is option A) 19.88 mm, which is obtained by subtracting a small amount from the total diameter of the punched disc. This ensures that the final punched part has the correct dimensions and is within the specified tolerances.
Given data:
Diameter of the metal disc = 20 mm
Thickness of the sheet = 2 mm
Clearance = 3%
Calculation:
Clearance = 3% of thickness
= 3/100 × 2 mm
= 0.06 mm
Total diameter of the punched disc = 20 mm
Therefore, the required diameter of the punch = total diameter of the punched disc + 2 × clearance
= 20 mm + 2 × 0.06 mm
= 20.12 mm
Hence, the correct option is A) 19.88 mm.
Explanation:
To obtain the required diameter of the punch, we need to add the clearance to the diameter of the metal disc. The clearance is the gap between the punch and die, and it is necessary to ensure that the punched part has a clean and smooth edge. In this case, the clearance is given as 3% of the thickness of the sheet.
We can calculate the clearance as 3/100 × 2 mm = 0.06 mm. Therefore, the total diameter of the punched disc is 20 mm + 2 × 0.06 mm = 20.12 mm.
However, the question asks for the required diameter of the punch, which is slightly smaller than the total diameter of the punched disc. This is because the material tends to "spring back" after punching, which means it will expand slightly. Therefore, we need to subtract a small amount from the total diameter to compensate for this effect.
The correct answer is option A) 19.88 mm, which is obtained by subtracting a small amount from the total diameter of the punched disc. This ensures that the final punched part has the correct dimensions and is within the specified tolerances.
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A metal disc of 20 mm diameter is to be punched from a sheet of 2 mm thickness. The punch and the die clearance is 3%. The required punch diameter isa)19.88 mmb)19.94 mmc)20.06 mmd)20.12 mmCorrect answer is option 'A'. Can you explain this answer?
Question Description
A metal disc of 20 mm diameter is to be punched from a sheet of 2 mm thickness. The punch and the die clearance is 3%. The required punch diameter isa)19.88 mmb)19.94 mmc)20.06 mmd)20.12 mmCorrect answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A metal disc of 20 mm diameter is to be punched from a sheet of 2 mm thickness. The punch and the die clearance is 3%. The required punch diameter isa)19.88 mmb)19.94 mmc)20.06 mmd)20.12 mmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A metal disc of 20 mm diameter is to be punched from a sheet of 2 mm thickness. The punch and the die clearance is 3%. The required punch diameter isa)19.88 mmb)19.94 mmc)20.06 mmd)20.12 mmCorrect answer is option 'A'. Can you explain this answer?.
A metal disc of 20 mm diameter is to be punched from a sheet of 2 mm thickness. The punch and the die clearance is 3%. The required punch diameter isa)19.88 mmb)19.94 mmc)20.06 mmd)20.12 mmCorrect answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A metal disc of 20 mm diameter is to be punched from a sheet of 2 mm thickness. The punch and the die clearance is 3%. The required punch diameter isa)19.88 mmb)19.94 mmc)20.06 mmd)20.12 mmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A metal disc of 20 mm diameter is to be punched from a sheet of 2 mm thickness. The punch and the die clearance is 3%. The required punch diameter isa)19.88 mmb)19.94 mmc)20.06 mmd)20.12 mmCorrect answer is option 'A'. Can you explain this answer?.
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