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A blank of 50 mm diameter is to be sheared from a sheet of 2.5 mm thickness. The required radial clearance between the die and the punch is 6% of sheet thickness. The punch and die diameter (mm) for this blanking operation respectively are
[PI 2008]
  • a)
    50.00 and 50.30
  • b)
    50.00 and 50.15
  • c)
    49.70 and 50.00
  • d)
    49.85 and 50.00
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A blank of 50 mm diameter is to be sheared from a sheet of 2.5 mm thic...

Total clearance = 2 × 0.15 = 0.3
Die Dia will be exact = 50 mm
Clearance will be provided on punch
= 50–0.30 = 49.70 mm
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Most Upvoted Answer
A blank of 50 mm diameter is to be sheared from a sheet of 2.5 mm thic...
To determine the punch and die diameter for the blanking operation, we need to consider the given specifications and calculations.

Given:
Sheet thickness = 2.5 mm
Radial clearance = 6% of sheet thickness

Step 1: Calculate the radial clearance
Radial clearance = 6% of sheet thickness = 6% of 2.5 mm = 0.06 * 2.5 mm = 0.15 mm

Step 2: Determine the final blank diameter
Blank diameter = Punch diameter + 2 * radial clearance

Since the blank diameter is given as 50 mm, we can write the equation as:
50 mm = Punch diameter + 2 * 0.15 mm

Step 3: Solve for the punch diameter
Punch diameter = 50 mm - 2 * 0.15 mm = 50 mm - 0.3 mm = 49.7 mm

Step 4: Determine the die diameter
The die diameter is equal to the punch diameter + 2 * radial clearance.
Die diameter = Punch diameter + 2 * 0.15 mm = 49.7 mm + 2 * 0.15 mm = 49.7 mm + 0.3 mm = 50 mm

Therefore, the punch diameter is 49.7 mm and the die diameter is 50 mm. Hence, the correct answer is option 'C' (49.7 mm and 50 mm).
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A blank of 50 mm diameter is to be sheared from a sheet of 2.5 mm thickness. The required radial clearance between the die and the punch is 6% of sheet thickness. The punch and die diameter (mm) for this blanking operation respectively are[PI 2008]a)50.00 and 50.30b)50.00 and 50.15c)49.70 and 50.00d)49.85 and 50.00Correct answer is option 'C'. Can you explain this answer?
Question Description
A blank of 50 mm diameter is to be sheared from a sheet of 2.5 mm thickness. The required radial clearance between the die and the punch is 6% of sheet thickness. The punch and die diameter (mm) for this blanking operation respectively are[PI 2008]a)50.00 and 50.30b)50.00 and 50.15c)49.70 and 50.00d)49.85 and 50.00Correct answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A blank of 50 mm diameter is to be sheared from a sheet of 2.5 mm thickness. The required radial clearance between the die and the punch is 6% of sheet thickness. The punch and die diameter (mm) for this blanking operation respectively are[PI 2008]a)50.00 and 50.30b)50.00 and 50.15c)49.70 and 50.00d)49.85 and 50.00Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A blank of 50 mm diameter is to be sheared from a sheet of 2.5 mm thickness. The required radial clearance between the die and the punch is 6% of sheet thickness. The punch and die diameter (mm) for this blanking operation respectively are[PI 2008]a)50.00 and 50.30b)50.00 and 50.15c)49.70 and 50.00d)49.85 and 50.00Correct answer is option 'C'. Can you explain this answer?.
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