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The thickness of metallic sheet is reduced from an initial thickness of 16 mm to a final required thickness in one single pass rolling with a pair of cylindrical rollers each of diameter of 400 mm and angle of bits 9.8°. The final required thickness is
- a)12 mm
- b)13.55 mm
- c)10.03 mm
- d)15 mm
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
The thickness of metallic sheet is reduced from an initial thickness o...
Given,
Initial thickness (h1) = 16 mm
Final thickness (h2)
Roll diameter = 400 mm
We know that
Initial thickness (h1) = 16 mm
Final thickness (h2)
Roll diameter = 400 mm
We know that
Most Upvoted Answer
The thickness of metallic sheet is reduced from an initial thickness o...
Given:
Initial thickness of metallic sheet (h1) = 16 mm
Diameter of cylindrical rollers (D) = 400 mm
Angle of bite (α) = 9.8°
To find:
Final required thickness of metallic sheet (h2)
Solution:
1. Calculating the reduction in thickness:
The reduction in thickness (Δh) can be calculated using the formula:
Δh = h1 - h2
2. Calculating the effective diameter of rollers:
The effective diameter of the rollers (De) can be calculated using the formula:
De = D × cos(α)
3. Calculating the reduction in thickness due to one pass rolling:
The reduction in thickness due to one pass rolling (Δh1) can be calculated using the formula:
Δh1 = De - D
4. Calculating the number of passes required:
The number of passes required (n) can be calculated using the formula:
n = Δh/Δh1
5. Calculating the final required thickness:
The final required thickness of the metallic sheet (h2) can be calculated using the formula:
h2 = h1 - (n × Δh1)
Now, let's calculate the values step by step:
- Calculating the reduction in thickness:
Δh = h1 - h2
- Calculating the effective diameter of rollers:
De = D × cos(α)
- Calculating the reduction in thickness due to one pass rolling:
Δh1 = De - D
- Calculating the number of passes required:
n = Δh/Δh1
- Calculating the final required thickness:
h2 = h1 - (n × Δh1)
Substituting the given values:
Initial thickness of metallic sheet (h1) = 16 mm
Diameter of cylindrical rollers (D) = 400 mm
Angle of bite (α) = 9.8°
Calculating the reduction in thickness:
Δh = h1 - h2
Δh = 16 mm - h2
Calculating the effective diameter of rollers:
De = D × cos(α)
De = 400 mm × cos(9.8°)
Calculating the reduction in thickness due to one pass rolling:
Δh1 = De - D
Δh1 = (400 mm × cos(9.8°)) - 400 mm
Calculating the number of passes required:
n = Δh/Δh1
n = (16 mm - h2)/[(400 mm × cos(9.8°)) - 400 mm]
Calculating the final required thickness:
h2 = h1 - (n × Δh1)
h2 = 16 mm - [(16 mm - h2)/[(400 mm × cos(9.8°)) - 400 mm]] × [(400 mm × cos(9.8°)) - 400 mm]
After solving the equations, we find that the
Initial thickness of metallic sheet (h1) = 16 mm
Diameter of cylindrical rollers (D) = 400 mm
Angle of bite (α) = 9.8°
To find:
Final required thickness of metallic sheet (h2)
Solution:
1. Calculating the reduction in thickness:
The reduction in thickness (Δh) can be calculated using the formula:
Δh = h1 - h2
2. Calculating the effective diameter of rollers:
The effective diameter of the rollers (De) can be calculated using the formula:
De = D × cos(α)
3. Calculating the reduction in thickness due to one pass rolling:
The reduction in thickness due to one pass rolling (Δh1) can be calculated using the formula:
Δh1 = De - D
4. Calculating the number of passes required:
The number of passes required (n) can be calculated using the formula:
n = Δh/Δh1
5. Calculating the final required thickness:
The final required thickness of the metallic sheet (h2) can be calculated using the formula:
h2 = h1 - (n × Δh1)
Now, let's calculate the values step by step:
- Calculating the reduction in thickness:
Δh = h1 - h2
- Calculating the effective diameter of rollers:
De = D × cos(α)
- Calculating the reduction in thickness due to one pass rolling:
Δh1 = De - D
- Calculating the number of passes required:
n = Δh/Δh1
- Calculating the final required thickness:
h2 = h1 - (n × Δh1)
Substituting the given values:
Initial thickness of metallic sheet (h1) = 16 mm
Diameter of cylindrical rollers (D) = 400 mm
Angle of bite (α) = 9.8°
Calculating the reduction in thickness:
Δh = h1 - h2
Δh = 16 mm - h2
Calculating the effective diameter of rollers:
De = D × cos(α)
De = 400 mm × cos(9.8°)
Calculating the reduction in thickness due to one pass rolling:
Δh1 = De - D
Δh1 = (400 mm × cos(9.8°)) - 400 mm
Calculating the number of passes required:
n = Δh/Δh1
n = (16 mm - h2)/[(400 mm × cos(9.8°)) - 400 mm]
Calculating the final required thickness:
h2 = h1 - (n × Δh1)
h2 = 16 mm - [(16 mm - h2)/[(400 mm × cos(9.8°)) - 400 mm]] × [(400 mm × cos(9.8°)) - 400 mm]
After solving the equations, we find that the
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The thickness of metallic sheet is reduced from an initial thickness o...
C
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The thickness of metallic sheet is reduced from an initial thickness of 16 mm to a final required thickness in one single pass rolling with a pair of cylindrical rollers each of diameter of 400 mm and angle of bits 9.8°. The final required thickness isa)12 mmb)13.55 mmc)10.03 mmd)15 mmCorrect answer is option 'C'. Can you explain this answer?
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The thickness of metallic sheet is reduced from an initial thickness of 16 mm to a final required thickness in one single pass rolling with a pair of cylindrical rollers each of diameter of 400 mm and angle of bits 9.8°. The final required thickness isa)12 mmb)13.55 mmc)10.03 mmd)15 mmCorrect answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about The thickness of metallic sheet is reduced from an initial thickness of 16 mm to a final required thickness in one single pass rolling with a pair of cylindrical rollers each of diameter of 400 mm and angle of bits 9.8°. The final required thickness isa)12 mmb)13.55 mmc)10.03 mmd)15 mmCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The thickness of metallic sheet is reduced from an initial thickness of 16 mm to a final required thickness in one single pass rolling with a pair of cylindrical rollers each of diameter of 400 mm and angle of bits 9.8°. The final required thickness isa)12 mmb)13.55 mmc)10.03 mmd)15 mmCorrect answer is option 'C'. Can you explain this answer?.
The thickness of metallic sheet is reduced from an initial thickness of 16 mm to a final required thickness in one single pass rolling with a pair of cylindrical rollers each of diameter of 400 mm and angle of bits 9.8°. The final required thickness isa)12 mmb)13.55 mmc)10.03 mmd)15 mmCorrect answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about The thickness of metallic sheet is reduced from an initial thickness of 16 mm to a final required thickness in one single pass rolling with a pair of cylindrical rollers each of diameter of 400 mm and angle of bits 9.8°. The final required thickness isa)12 mmb)13.55 mmc)10.03 mmd)15 mmCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The thickness of metallic sheet is reduced from an initial thickness of 16 mm to a final required thickness in one single pass rolling with a pair of cylindrical rollers each of diameter of 400 mm and angle of bits 9.8°. The final required thickness isa)12 mmb)13.55 mmc)10.03 mmd)15 mmCorrect answer is option 'C'. Can you explain this answer?.
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