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The thickness of a metallic sheet is reduced from an initial value of 16 mm to a final value of 10 mm in one single pass rolling with a pair of cylindrical rollers each of diameter of 400 mm. The bite angle in degree will be
[ME 2007]
  • a)
    5.936
  • b)
    7.936
  • c)
    8.936
  • d)
    9.936
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The thickness of a metallic sheet is reduced from an initial value of ...

tan α = 0.173
∴ Bite angle, α = tan-1 (0.173) = 9.936°
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Most Upvoted Answer
The thickness of a metallic sheet is reduced from an initial value of ...

tan α = 0.173
∴ Bite angle, α = tan-1 (0.173) = 9.936°
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Community Answer
The thickness of a metallic sheet is reduced from an initial value of ...
Given:
- Initial thickness of metallic sheet = 16 mm
- Final thickness of metallic sheet = 10 mm
- Diameter of cylindrical rollers = 400 mm

To find:
- Bite angle in degrees

Formula:
The reduction in thickness of the sheet can be calculated using the formula:

R = (D - d) / D

Where:
- R is the reduction in thickness
- D is the initial diameter of the roller
- d is the final diameter of the roller

Calculation:
Given that the initial thickness of the sheet is 16 mm and the final thickness is 10 mm, we can calculate the reduction in thickness:

R = (16 - 10) / 16 = 6 / 16 = 0.375

We are also given that the diameter of the cylindrical rollers is 400 mm. Using this information, we can calculate the reduction in thickness due to one pass rolling:

R = (D - d) / D
0.375 = (400 - d) / 400

Solving for d, we get:
d = 400 - 0.375 * 400
d = 400 - 150
d = 250 mm

The bite angle can be calculated using the formula:

Bite angle = (diameter of roller - diameter of sheet) / diameter of sheet * 360

Substituting the values, we get:
Bite angle = (400 - 250) / 250 * 360
Bite angle = 150 / 250 * 360
Bite angle = 0.6 * 360
Bite angle = 216 degrees

Therefore, the bite angle is 216 degrees.
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