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Circular blanks of 35 mm dia are punched from a steel sheet of 2 mm thickness. If the clearance per side between the punch and die is to be kept as 40 microns. The sizes of punch and die should respectively be
[PI 2007]
  • a)
    35 and 35.040
  • b)
    34.92 and 35
  • c)
    35 and 35.080
  • d)
    35.040 and 34.92
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Circular blanks of 35 mm dia are punched from a steel sheet of 2 mm th...
Dia of Die = 35 mm
Dia of Punch = 35 – 2 × 0.04 = 34.92mm
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Most Upvoted Answer
Circular blanks of 35 mm dia are punched from a steel sheet of 2 mm th...
Given:
- Diameter of the circular blanks (d): 35 mm
- Thickness of the steel sheet (t): 2 mm
- Clearance per side between the punch and die (c): 40 microns (0.04 mm)

To find:
- Sizes of punch and die

Solution:
The size of the punch and die can be determined by considering the clearance required between them.

Clearance:
The clearance is the gap between the punch and die that allows for the deformation of the material during the punching process. It is necessary to prevent the material from getting trapped between the punch and die, which could lead to a poor-quality punched hole or damage to the punch and die.

Clearance Calculation:
The clearance required per side is given as 40 microns, which means there should be a total clearance of 80 microns (0.08 mm) between the punch and die.

Clearance (c) = Total clearance / 2
c = 0.08 mm / 2 = 0.04 mm

Diameter of Punch and Die:
The diameter of the punch and die can be calculated by adding the clearance to the diameter of the circular blank.

Diameter of punch = Diameter of blank + 2 * Clearance
Diameter of punch = 35 mm + 2 * 0.04 mm = 35.08 mm

Diameter of die = Diameter of punch - 2 * Clearance
Diameter of die = 35.08 mm - 2 * 0.04 mm = 34.92 mm

Final Answer:
The sizes of the punch and die should be 34.92 mm and 35.08 mm, respectively. Therefore, option B is the correct answer.
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Circular blanks of 35 mm dia are punched from a steel sheet of 2 mm thickness. If the clearance per side between the punch and die is to be kept as 40 microns. The sizes of punch and die should respectively be[PI 2007]a)35 and 35.040b)34.92 and 35c)35 and 35.080d)35.040 and 34.92Correct answer is option 'B'. Can you explain this answer?
Question Description
Circular blanks of 35 mm dia are punched from a steel sheet of 2 mm thickness. If the clearance per side between the punch and die is to be kept as 40 microns. The sizes of punch and die should respectively be[PI 2007]a)35 and 35.040b)34.92 and 35c)35 and 35.080d)35.040 and 34.92Correct answer is option 'B'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Circular blanks of 35 mm dia are punched from a steel sheet of 2 mm thickness. If the clearance per side between the punch and die is to be kept as 40 microns. The sizes of punch and die should respectively be[PI 2007]a)35 and 35.040b)34.92 and 35c)35 and 35.080d)35.040 and 34.92Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Circular blanks of 35 mm dia are punched from a steel sheet of 2 mm thickness. If the clearance per side between the punch and die is to be kept as 40 microns. The sizes of punch and die should respectively be[PI 2007]a)35 and 35.040b)34.92 and 35c)35 and 35.080d)35.040 and 34.92Correct answer is option 'B'. Can you explain this answer?.
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