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Chemical analysis of a carbon compound gave the following percentage composition by weight of the elements
present in it. Carbon = 10.06%, hydrogen = 0.84%, chlorine = 89.10%. Calculate the empirical formula of the compound :-
present in it. Carbon = 10.06%, hydrogen = 0.84%, chlorine = 89.10%. Calculate the empirical formula of the compound :-
- a)C2H2Cl2
- b)CHCl2
- c)CHCl3
- d)C4H4Cl4
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
Chemical analysis of a carbon compound gave the following percentage c...
Cl = 71.7 % , moles = 71.7/35.5 = 2.02
H = 4.04 %, moes = 4.04/1 = 4.04
C = 24.26 %, moles = 24.26/12 = 2.02
mole ratio C:H:Cl = 2:4:2 = 1:2:1
Empirical formula = CH2Cl.
E.F wt = 12+2+35.5 = 49.5
M.wt = 99 (given)
n = M.wt/E.F wt = 99/49.5 = 2
Therefore MF = (E.F)n = (CH2Cl)2
Most Upvoted Answer
Chemical analysis of a carbon compound gave the following percentage c...
Given percentage composition by weight of the elements present in a carbon compound are as follows:
Carbon = 10.06%
Hydrogen = 0.84%
Chlorine = 89.10%
To find the empirical formula, we need to determine the simplest whole-number ratio of atoms in the compound.
Let us assume the compound has 100 g of the sample, then we can find the masses of the individual elements present in the sample as follows:
Mass of carbon = 10.06 g
Mass of hydrogen = 0.84 g
Mass of chlorine = 89.10 g
To find the empirical formula, we need to convert the mass of each element to moles using their respective atomic masses. The atomic masses of carbon, hydrogen, and chlorine are 12, 1, and 35.5 respectively.
Number of moles of carbon = 10.06 g / 12 g/mol = 0.8383
Number of moles of hydrogen = 0.84 g / 1 g/mol = 0.84
Number of moles of chlorine = 89.10 g / 35.5 g/mol = 2.51
Next, we need to find the simplest whole-number ratio of atoms by dividing each of the mole values by the smallest mole value. In this case, the smallest mole value is 0.8383.
Number of moles of carbon = 0.8383 / 0.8383 = 1
Number of moles of hydrogen = 0.84 / 0.8383 = 1.001
Number of moles of chlorine = 2.51 / 0.8383 = 2.994
The empirical formula is the simplest whole-number ratio of atoms, so we need to round off the number of moles of hydrogen and chlorine to the nearest whole number.
Number of moles of carbon = 1
Number of moles of hydrogen = 1
Number of moles of chlorine = 3
Therefore, the empirical formula of the compound is CHCl3.
Carbon = 10.06%
Hydrogen = 0.84%
Chlorine = 89.10%
To find the empirical formula, we need to determine the simplest whole-number ratio of atoms in the compound.
Let us assume the compound has 100 g of the sample, then we can find the masses of the individual elements present in the sample as follows:
Mass of carbon = 10.06 g
Mass of hydrogen = 0.84 g
Mass of chlorine = 89.10 g
To find the empirical formula, we need to convert the mass of each element to moles using their respective atomic masses. The atomic masses of carbon, hydrogen, and chlorine are 12, 1, and 35.5 respectively.
Number of moles of carbon = 10.06 g / 12 g/mol = 0.8383
Number of moles of hydrogen = 0.84 g / 1 g/mol = 0.84
Number of moles of chlorine = 89.10 g / 35.5 g/mol = 2.51
Next, we need to find the simplest whole-number ratio of atoms by dividing each of the mole values by the smallest mole value. In this case, the smallest mole value is 0.8383.
Number of moles of carbon = 0.8383 / 0.8383 = 1
Number of moles of hydrogen = 0.84 / 0.8383 = 1.001
Number of moles of chlorine = 2.51 / 0.8383 = 2.994
The empirical formula is the simplest whole-number ratio of atoms, so we need to round off the number of moles of hydrogen and chlorine to the nearest whole number.
Number of moles of carbon = 1
Number of moles of hydrogen = 1
Number of moles of chlorine = 3
Therefore, the empirical formula of the compound is CHCl3.
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Chemical analysis of a carbon compound gave the following percentage composition by weight of the elementspresent in it. Carbon = 10.06%, hydrogen = 0.84%, chlorine = 89.10%. Calculate the empirical formula ofthe compound :-a)C2H2Cl2b)CHCl2c)CHCl3d)C4H4Cl4Correct answer is option 'C'. Can you explain this answer?
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Chemical analysis of a carbon compound gave the following percentage composition by weight of the elementspresent in it. Carbon = 10.06%, hydrogen = 0.84%, chlorine = 89.10%. Calculate the empirical formula ofthe compound :-a)C2H2Cl2b)CHCl2c)CHCl3d)C4H4Cl4Correct answer is option 'C'. Can you explain this answer? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about Chemical analysis of a carbon compound gave the following percentage composition by weight of the elementspresent in it. Carbon = 10.06%, hydrogen = 0.84%, chlorine = 89.10%. Calculate the empirical formula ofthe compound :-a)C2H2Cl2b)CHCl2c)CHCl3d)C4H4Cl4Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Chemical analysis of a carbon compound gave the following percentage composition by weight of the elementspresent in it. Carbon = 10.06%, hydrogen = 0.84%, chlorine = 89.10%. Calculate the empirical formula ofthe compound :-a)C2H2Cl2b)CHCl2c)CHCl3d)C4H4Cl4Correct answer is option 'C'. Can you explain this answer?.
Chemical analysis of a carbon compound gave the following percentage composition by weight of the elementspresent in it. Carbon = 10.06%, hydrogen = 0.84%, chlorine = 89.10%. Calculate the empirical formula ofthe compound :-a)C2H2Cl2b)CHCl2c)CHCl3d)C4H4Cl4Correct answer is option 'C'. Can you explain this answer? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about Chemical analysis of a carbon compound gave the following percentage composition by weight of the elementspresent in it. Carbon = 10.06%, hydrogen = 0.84%, chlorine = 89.10%. Calculate the empirical formula ofthe compound :-a)C2H2Cl2b)CHCl2c)CHCl3d)C4H4Cl4Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Chemical analysis of a carbon compound gave the following percentage composition by weight of the elementspresent in it. Carbon = 10.06%, hydrogen = 0.84%, chlorine = 89.10%. Calculate the empirical formula ofthe compound :-a)C2H2Cl2b)CHCl2c)CHCl3d)C4H4Cl4Correct answer is option 'C'. Can you explain this answer?.
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Chemical analysis of a carbon compound gave the following percentage composition by weight of the elementspresent in it. Carbon = 10.06%, hydrogen = 0.84%, chlorine = 89.10%. Calculate the empirical formula ofthe compound :-a)C2H2Cl2b)CHCl2c)CHCl3d)C4H4Cl4Correct answer is option 'C'. Can you explain this answer?, a detailed solution for Chemical analysis of a carbon compound gave the following percentage composition by weight of the elementspresent in it. Carbon = 10.06%, hydrogen = 0.84%, chlorine = 89.10%. Calculate the empirical formula ofthe compound :-a)C2H2Cl2b)CHCl2c)CHCl3d)C4H4Cl4Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of Chemical analysis of a carbon compound gave the following percentage composition by weight of the elementspresent in it. Carbon = 10.06%, hydrogen = 0.84%, chlorine = 89.10%. Calculate the empirical formula ofthe compound :-a)C2H2Cl2b)CHCl2c)CHCl3d)C4H4Cl4Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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