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A shaft of dimension 40 ± 0.1mm is produced with a circularity error of 0.05mm on maximum material limit. To produce clearance fit between the hole and shaft, the minimum size of the hole required is
- a)39.90mm
- b)39.95mm
- c)40.10mm
- d)40.15mm
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
A shaft of dimension 40 ± 0.1mm is produced with a circularity er...
Mm size of Hole = L-limit of hole
= Maximum Material Limit (MML) of hole
= MML of shaft +circularity error
= 40.1 +0.05 =40.15 mm
= Maximum Material Limit (MML) of hole
= MML of shaft +circularity error
= 40.1 +0.05 =40.15 mm
Most Upvoted Answer
A shaft of dimension 40 ± 0.1mm is produced with a circularity er...
To determine the minimum size of the hole required to produce a clearance fit with the given shaft, we need to consider the dimensions and tolerances provided.
Given:
Shaft dimension = 40 ± 0.1 mm
Circularity error = 0.05 mm (on maximum material limit)
Determining the Maximum Material Limit:
The maximum material limit for the shaft can be calculated by adding the dimension and the tolerance:
Maximum Material Limit = 40 + 0.1 = 40.1 mm
Determining the Minimum Material Limit:
The minimum material limit for the shaft can be calculated by subtracting the tolerance from the dimension:
Minimum Material Limit = 40 - 0.1 = 39.9 mm
Determining the Hole Size:
To produce a clearance fit, the hole size should be larger than the maximum material limit of the shaft. Therefore, the minimum size of the hole required is 40.1 mm.
Answer: The correct option is 'D' (40.15 mm)
Explanation:
The minimum size of the hole required is determined by considering the maximum material limit of the shaft. Since the circularity error is given on the maximum material limit, the hole size needs to be larger than the maximum material limit to ensure a clearance fit. Therefore, the correct answer is option 'D' (40.15 mm).
Summary:
- Shaft dimension: 40 ± 0.1 mm
- Circularity error: 0.05 mm (on maximum material limit)
- Maximum Material Limit for the shaft: 40 + 0.1 = 40.1 mm
- Minimum Material Limit for the shaft: 40 - 0.1 = 39.9 mm
- To produce a clearance fit, the hole size should be larger than the maximum material limit of the shaft, which is 40.1 mm.
- Therefore, the minimum size of the hole required is 40.15 mm.
Note: It is important to carefully analyze the given information and consider the appropriate calculations to determine the correct answer.
Given:
Shaft dimension = 40 ± 0.1 mm
Circularity error = 0.05 mm (on maximum material limit)
Determining the Maximum Material Limit:
The maximum material limit for the shaft can be calculated by adding the dimension and the tolerance:
Maximum Material Limit = 40 + 0.1 = 40.1 mm
Determining the Minimum Material Limit:
The minimum material limit for the shaft can be calculated by subtracting the tolerance from the dimension:
Minimum Material Limit = 40 - 0.1 = 39.9 mm
Determining the Hole Size:
To produce a clearance fit, the hole size should be larger than the maximum material limit of the shaft. Therefore, the minimum size of the hole required is 40.1 mm.
Answer: The correct option is 'D' (40.15 mm)
Explanation:
The minimum size of the hole required is determined by considering the maximum material limit of the shaft. Since the circularity error is given on the maximum material limit, the hole size needs to be larger than the maximum material limit to ensure a clearance fit. Therefore, the correct answer is option 'D' (40.15 mm).
Summary:
- Shaft dimension: 40 ± 0.1 mm
- Circularity error: 0.05 mm (on maximum material limit)
- Maximum Material Limit for the shaft: 40 + 0.1 = 40.1 mm
- Minimum Material Limit for the shaft: 40 - 0.1 = 39.9 mm
- To produce a clearance fit, the hole size should be larger than the maximum material limit of the shaft, which is 40.1 mm.
- Therefore, the minimum size of the hole required is 40.15 mm.
Note: It is important to carefully analyze the given information and consider the appropriate calculations to determine the correct answer.
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A shaft of dimension 40 ± 0.1mm is produced with a circularity error of 0.05mm on maximum material limit. To produce clearance fit between the hole and shaft, the minimum size of the hole required isa)39.90mmb)39.95mmc)40.10mmd)40.15mmCorrect answer is option 'D'. Can you explain this answer?
Question Description
A shaft of dimension 40 ± 0.1mm is produced with a circularity error of 0.05mm on maximum material limit. To produce clearance fit between the hole and shaft, the minimum size of the hole required isa)39.90mmb)39.95mmc)40.10mmd)40.15mmCorrect answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A shaft of dimension 40 ± 0.1mm is produced with a circularity error of 0.05mm on maximum material limit. To produce clearance fit between the hole and shaft, the minimum size of the hole required isa)39.90mmb)39.95mmc)40.10mmd)40.15mmCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A shaft of dimension 40 ± 0.1mm is produced with a circularity error of 0.05mm on maximum material limit. To produce clearance fit between the hole and shaft, the minimum size of the hole required isa)39.90mmb)39.95mmc)40.10mmd)40.15mmCorrect answer is option 'D'. Can you explain this answer?.
A shaft of dimension 40 ± 0.1mm is produced with a circularity error of 0.05mm on maximum material limit. To produce clearance fit between the hole and shaft, the minimum size of the hole required isa)39.90mmb)39.95mmc)40.10mmd)40.15mmCorrect answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A shaft of dimension 40 ± 0.1mm is produced with a circularity error of 0.05mm on maximum material limit. To produce clearance fit between the hole and shaft, the minimum size of the hole required isa)39.90mmb)39.95mmc)40.10mmd)40.15mmCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A shaft of dimension 40 ± 0.1mm is produced with a circularity error of 0.05mm on maximum material limit. To produce clearance fit between the hole and shaft, the minimum size of the hole required isa)39.90mmb)39.95mmc)40.10mmd)40.15mmCorrect answer is option 'D'. Can you explain this answer?.
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