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A cast product of a particular material has dimensions, 75 mm× 125 mm × 20 mm. The total solidification time for the cast product is found to be 2.0 minutes as calculated using Chvorinovs rule having the index n = 2 . If under the identical casting conditions, the cast product shape is changed to a cylinder having diameter = 50 mm and height = 50 mm, the total solidification time will be ______minutes(round off to the two decimal places).Correct answer is '2.82'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A cast product of a particular material has dimensions, 75 mm× 125 mm × 20 mm. The total solidification time for the cast product is found to be 2.0 minutes as calculated using Chvorinovs rule having the index n = 2 . If under the identical casting conditions, the cast product shape is changed to a cylinder having diameter = 50 mm and height = 50 mm, the total solidification time will be ______minutes(round off to the two decimal places).Correct answer is '2.82'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cast product of a particular material has dimensions, 75 mm× 125 mm × 20 mm. The total solidification time for the cast product is found to be 2.0 minutes as calculated using Chvorinovs rule having the index n = 2 . If under the identical casting conditions, the cast product shape is changed to a cylinder having diameter = 50 mm and height = 50 mm, the total solidification time will be ______minutes(round off to the two decimal places).Correct answer is '2.82'. Can you explain this answer?.

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Here you can find the meaning of A cast product of a particular material has dimensions, 75 mm× 125 mm × 20 mm. The total solidification time for the cast product is found to be 2.0 minutes as calculated using Chvorinovs rule having the index n = 2 . If under the identical casting conditions, the cast product shape is changed to a cylinder having diameter = 50 mm and height = 50 mm, the total solidification time will be ______minutes(round off to the two decimal places).Correct answer is '2.82'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A cast product of a particular material has dimensions, 75 mm× 125 mm × 20 mm. The total solidification time for the cast product is found to be 2.0 minutes as calculated using Chvorinovs rule having the index n = 2 . If under the identical casting conditions, the cast product shape is changed to a cylinder having diameter = 50 mm and height = 50 mm, the total solidification time will be ______minutes(round off to the two decimal places).Correct answer is '2.82'. Can you explain this answer?, a detailed solution for A cast product of a particular material has dimensions, 75 mm× 125 mm × 20 mm. The total solidification time for the cast product is found to be 2.0 minutes as calculated using Chvorinovs rule having the index n = 2 . If under the identical casting conditions, the cast product shape is changed to a cylinder having diameter = 50 mm and height = 50 mm, the total solidification time will be ______minutes(round off to the two decimal places).Correct answer is '2.82'. Can you explain this answer? has been provided alongside types of A cast product of a particular material has dimensions, 75 mm× 125 mm × 20 mm. The total solidification time for the cast product is found to be 2.0 minutes as calculated using Chvorinovs rule having the index n = 2 . If under the identical casting conditions, the cast product shape is changed to a cylinder having diameter = 50 mm and height = 50 mm, the total solidification time will be ______minutes(round off to the two decimal places).Correct answer is '2.82'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A cast product of a particular material has dimensions, 75 mm× 125 mm × 20 mm. The total solidification time for the cast product is found to be 2.0 minutes as calculated using Chvorinovs rule having the index n = 2 . If under the identical casting conditions, the cast product shape is changed to a cylinder having diameter = 50 mm and height = 50 mm, the total solidification time will be ______minutes(round off to the two decimal places).Correct answer is '2.82'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.