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T he rat io of the solidification time of two cylindrical risers of sizes 30 cm in diameter × 60 cm in height and
60 cm in diameter × 30 cm in height subjected to identical conditions of cooling
    Correct answer is between '0.60,0.70'. Can you explain this answer?
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    And 20 cm in diameter can be calculated using the Chvorinov's rule. This rule states that the solidification time is proportional to the square of the volume-to-surface area ratio of the casting. The formula for the solidification time is given as:

    t = K(V/A)^n

    where t is the solidification time, V is the volume of the casting, A is the surface area of the casting, K is a constant, and n is a constant exponent.

    Assuming that the risers have the same height, we can calculate their volumes and surface areas using the formulas:

    Volume = πr^2h
    Surface area = 2πrh + 2πr^2

    where r is the radius of the riser and h is the height of the riser.

    For the 30 cm diameter riser, the volume and surface area are:

    Volume = π(15)^2h = 225πh
    Surface area = 2π(15)h + 2π(15)^2 = 30πh + 450π

    For the 20 cm diameter riser, the volume and surface area are:

    Volume = π(10)^2h = 100πh
    Surface area = 2π(10)h + 2π(10)^2 = 20πh + 200π

    The volume-to-surface area ratio for the 30 cm diameter riser is:

    V/A = (225πh)/(30πh + 450π) = 225/480 ≈ 0.469

    The volume-to-surface area ratio for the 20 cm diameter riser is:

    V/A = (100πh)/(20πh + 200π) = 100/220 ≈ 0.455

    Using Chvorinov's rule, we can calculate the ratio of the solidification times as:

    (t1/t2) = [(V1/A1)^n]/[(V2/A2)^n]

    where t1 and t2 are the solidification times for the 30 cm and 20 cm diameter risers, respectively.

    Substituting the values, we get:

    (t1/t2) = [(0.469)^n]/[(0.455)^n]

    Since we do not know the value of n, we cannot calculate the exact ratio of the solidification times. However, we can say that the solidification time for the larger riser (30 cm diameter) will be longer than the solidification time for the smaller riser (20 cm diameter) due to its lower volume-to-surface area ratio.
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    T he rat io of the solidification time of two cylindrical risers of sizes 30 cm in diameter × 60 cm in height and60 cm in diameter × 30 cm in height subjected to identical conditions of coolingCorrect answer is between '0.60,0.70'. Can you explain this answer?
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    T he rat io of the solidification time of two cylindrical risers of sizes 30 cm in diameter × 60 cm in height and60 cm in diameter × 30 cm in height subjected to identical conditions of coolingCorrect answer is between '0.60,0.70'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about T he rat io of the solidification time of two cylindrical risers of sizes 30 cm in diameter × 60 cm in height and60 cm in diameter × 30 cm in height subjected to identical conditions of coolingCorrect answer is between '0.60,0.70'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for T he rat io of the solidification time of two cylindrical risers of sizes 30 cm in diameter × 60 cm in height and60 cm in diameter × 30 cm in height subjected to identical conditions of coolingCorrect answer is between '0.60,0.70'. Can you explain this answer?.
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