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If p and q are positive integers and X = 6p + 7q+23, what is the units digit of X?
(1) q = 2p – 11            
(2) q2 – 10q + 9 = 0
  • a)
    Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
  • b)
    Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient. 
  • c)
    BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient. 
  • d)
    EACH statement ALONE is sufficient. 
  • e)
    Statements (1) and (2) TOGETHER are NOT sufficient.
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
If p and q are positive integers and X = 6p + 7q+23, what is the units...
Steps 1 & 2: Understand Question and Draw Inferences
We are given that X = 6p + 7q+23, and we have to find the unit digit of X. The numbers p and q both are positive integers. Now, the unit digit of X will be the sum of the unit digits of 6p and 7q+23.
So, we have to find the unit digit of 6p and 7q+23.
Now, we know that the unit digit of 6 raised to any integer power is 6. So, the unit digit of 6p is 6.
And the cyclicity of 7 is 4 i.e. every 4th power of 7 has the same unit digit and cycles of power of 7 are 7, 9, 3, and 1.
So, the unit digit of the expression:
X = 6p + 7q+23 = (Unit Digit of 6p) + (Unit digit of 7q+23)
    = 6 + (Unit digit of 7q+23)
 So, the unit digit of 7q+23 will depend on the value of q. We have to find the value of q to determine the unit digit of X.   
Step 3: Analyze Statement 1
Statement 1 says: q = 2p – 11
 However, since we don’t know the value of p, we can’t determine the value of q.
 Hence, statement I is not sufficient to answer the question: What is the unit digit of X?  
 Step 4: Analyze Statement 2
Statement 2 says: 
q2 – 10q + 9 = 0
 q2 – 9q -q + 9 = 0 
(q – 9) (q – 1) = 0
 Thus, q= 1, 9
 Let’s consider both the values one by one:
  1. If q = 1
In this case, the expression 7q+23 becomes:
71+23 = 724
Since the cyclicity of 7 is 4 i.e. every 4th power of 7 has the same unit digit and cycles of power of 7 are 7, 9, 3, and 1.
And,
               24 = 4*6
So, the unit digit of 724 = 1
     2.  If q = 9
 In this case, the expression 7q+23 becomes:
79+23 = 732
Since the cyclicity of 7 is 4 i.e. every 4th power of 7 has the same unit digit and cycles of power of 7 are 7, 9, 3, and 1.
And,
               32 = 4*8 
So, the unit digit of 732 = 1
 So, in both the cases we get the unit digit of 7q+23 as 1. As derived in the first step, the unit digit of X
= 6 + (Unit digit of 7q+23) = 6 + 1 = 7
So, statement (2) alone is sufficient to answer the question: What is the unit digit of X?
Step 5: Analyze Both Statements Together (if needed)
Since statement (2) alone is sufficient to answer the question, we don’t need to perform this step.
Answer: Option (B)
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If p and q are positive integers and X = 6p + 7q+23, what is the units digit of X?(1) q = 2p – 11 (2) q2 – 10q + 9 = 0a)Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.b)Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.c)BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.d)EACH statement ALONE is sufficient.e)Statements (1) and (2) TOGETHER are NOT sufficient.Correct answer is option 'B'. Can you explain this answer?
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