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An electric current of 3A flows through a resistance of 10 ohm. It is being cooled by running water and is kept at temperature 300K, change in entropy per second of the resistance :
Select one:
Select one:
- a)No change
- b)4 joule deg-1
- c)0.3 joule deg-1
- d)3 joule deg-1
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
An electric current of 3A flows through a resistance of 10 ohm. It is ...
There is no change in the entropy of the resistance because there is no change in the state of wire.
The correct answer is: No change
The correct answer is: No change
Most Upvoted Answer
An electric current of 3A flows through a resistance of 10 ohm. It is ...
Explanation:
The entropy change of an object can be calculated using the formula:
ΔS = Q/T
where ΔS is the change in entropy, Q is the heat transfer, and T is the temperature.
In this scenario, the resistance is being cooled by running water, which means that heat is being transferred from the resistance to the water. The heat transfer can be calculated using the formula:
Q = I^2R
where I is the electric current and R is the resistance.
Calculating the heat transfer:
Using the given values, we can calculate the heat transfer as follows:
Q = (3A)^2 * 10Ω
Q = 9A^2 * 10Ω
Q = 90 joules
Calculating the change in entropy:
Now we can calculate the change in entropy using the formula:
ΔS = Q/T
Substituting the values, we get:
ΔS = 90 joules / 300K
ΔS = 0.3 joule deg-1
Conclusion:
The change in entropy per second of the resistance is 0.3 joule deg-1. Therefore, the correct answer is option 'A', which states that there is no change in entropy.
The entropy change of an object can be calculated using the formula:
ΔS = Q/T
where ΔS is the change in entropy, Q is the heat transfer, and T is the temperature.
In this scenario, the resistance is being cooled by running water, which means that heat is being transferred from the resistance to the water. The heat transfer can be calculated using the formula:
Q = I^2R
where I is the electric current and R is the resistance.
Calculating the heat transfer:
Using the given values, we can calculate the heat transfer as follows:
Q = (3A)^2 * 10Ω
Q = 9A^2 * 10Ω
Q = 90 joules
Calculating the change in entropy:
Now we can calculate the change in entropy using the formula:
ΔS = Q/T
Substituting the values, we get:
ΔS = 90 joules / 300K
ΔS = 0.3 joule deg-1
Conclusion:
The change in entropy per second of the resistance is 0.3 joule deg-1. Therefore, the correct answer is option 'A', which states that there is no change in entropy.
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