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A capacitor-start single phase induction motor is switched on to supply with its capacitor and replaced by an inductor of equivalent reactance value. It will:
  • a)
    Start and then stop
  • b)
    Start and run slowly
  • c)
    Start and run at a rated speed
  • d)
    Not start at all
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A capacitor-start single phase induction motor is switched on to suppl...
In 1-phase induction motors, we are unable to get starting torque. So, we mostly use permanent capacitor split phase starting method. Its main aim is to split the single-phase supply into 2 phases, having time displacement of 90 degrees, also mechanically the 2 windings are placed 90 degrees in space. It gives rotating magnetic field which produces a starting torque & makes it a self-starting motor.
If inductor is used, the motor would not start even if having same reactance. Since coils are inductive so a capacitor or some phase splitting is necessary.
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Most Upvoted Answer
A capacitor-start single phase induction motor is switched on to suppl...
Capacitor-Start Single Phase Induction Motor

A capacitor-start single phase induction motor is a type of motor used for various applications, such as in household appliances and small industrial machinery. It is designed to provide high starting torque while operating on a single-phase power supply.

Function of the Capacitor

The capacitor in a capacitor-start motor is used to create a phase shift between the main winding and the auxiliary winding, which helps to generate a rotating magnetic field. This rotating magnetic field initiates the rotation of the motor's rotor and allows it to start.

Replacing the Capacitor with an Inductor

When the capacitor in a capacitor-start motor is replaced with an inductor of equivalent reactance value, the phase shift between the main and auxiliary windings is eliminated. As a result, the motor is unable to generate a rotating magnetic field necessary for starting and running.

Explanation of the Correct Answer

The correct answer is option 'D' - the motor will not start at all. This is because without the phase shift created by the capacitor, the motor lacks the necessary starting torque to initiate rotation. The absence of a rotating magnetic field prevents the motor from starting and running.

Conclusion

In summary, a capacitor-start single phase induction motor relies on the presence of a capacitor to create a phase shift and generate a rotating magnetic field for starting and running. Replacing the capacitor with an inductor of equivalent reactance value eliminates the phase shift, resulting in the motor being unable to start.
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A capacitor-start single phase induction motor is switched on to supply with its capacitor and replaced by an inductor of equivalent reactance value. It will:a)Start and then stopb)Start and run slowlyc)Start and run at a rated speedd)Not start at allCorrect answer is option 'D'. Can you explain this answer?
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A capacitor-start single phase induction motor is switched on to supply with its capacitor and replaced by an inductor of equivalent reactance value. It will:a)Start and then stopb)Start and run slowlyc)Start and run at a rated speedd)Not start at allCorrect answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A capacitor-start single phase induction motor is switched on to supply with its capacitor and replaced by an inductor of equivalent reactance value. It will:a)Start and then stopb)Start and run slowlyc)Start and run at a rated speedd)Not start at allCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A capacitor-start single phase induction motor is switched on to supply with its capacitor and replaced by an inductor of equivalent reactance value. It will:a)Start and then stopb)Start and run slowlyc)Start and run at a rated speedd)Not start at allCorrect answer is option 'D'. Can you explain this answer?.
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