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A sample of an ideal gas with initial pressure p and volume V is taken through an isothermal expansion proceed during which the change in entropy is found to be ΔS. The universal gas constant is R. Then, the work done by the gas is given by :
- a)(pVΔS)\(nR)
- b)(pΔS)\(nRV)
- c)pV
- d)(nRΔS)
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A sample of an ideal gas with initial pressure p and volume V is taken...
By ideal gas equation,
pV = nRT ...(i)
and
...(ii)
Multiplying Equation (i) and (ii),
pVΔQ = nRΔS
⇒
∴ For isothermal expansion ΔV = 0
The correct answer is: (pVΔS)\(nR)
pV = nRT ...(i)
and
...(ii)Multiplying Equation (i) and (ii),
pVΔQ = nRΔS
⇒
∴ For isothermal expansion ΔV = 0
The correct answer is: (pVΔS)\(nR)
Most Upvoted Answer
A sample of an ideal gas with initial pressure p and volume V is taken...
To determine the change in entropy during an isothermal expansion of an ideal gas, we can use the equation for entropy change:
ΔS = nR ln(V2/V1)
Where:
ΔS = change in entropy
n = number of moles
R = gas constant
V2 = final volume
V1 = initial volume
In this case, the initial pressure and volume of the gas are given as p and V, respectively. Since the process is isothermal, the temperature remains constant throughout the expansion.
To find the final volume, we need more information about the process or any constraints given. Without this information, we cannot determine the specific value of ΔS.
ΔS = nR ln(V2/V1)
Where:
ΔS = change in entropy
n = number of moles
R = gas constant
V2 = final volume
V1 = initial volume
In this case, the initial pressure and volume of the gas are given as p and V, respectively. Since the process is isothermal, the temperature remains constant throughout the expansion.
To find the final volume, we need more information about the process or any constraints given. Without this information, we cannot determine the specific value of ΔS.
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A sample of an ideal gas with initial pressure p and volume V is taken...
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A sample of an ideal gas with initial pressure p and volume V is taken through an isothermal expansion proceed during which the change in entropy is found to be ΔS. The universal gas constant is R. Then, the work done by the gas is given by :a)(pVΔS)\(nR)b)(pΔS)\(nRV)c)pVd)(nRΔS)Correct answer is option 'A'. Can you explain this answer?
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