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A bob is hanging over a pulley inside a car through a string. The second end of the string is in the hand of a person standing in the car. The car is moving with constant acceleration a directed horizontally as shown in figure. Other end of the string is pulled with constant acceleration a vertically downward. The tension in the string is equal to :



  • a)

  • b)

  • c)

  • d)

Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A bob is hanging over a pulley inside a car through a string. The seco...

Free Body diagram in the frame of the car
Applying Newton’s law perpendicular to string

Applying Newton’s law along string 

The correct answer is: 
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Most Upvoted Answer
A bob is hanging over a pulley inside a car through a string. The seco...


Free Body diagram in the frame of the car


It is given that a bob is hanging over a pulley inside a car through a string the second end of the string is in the hand of a person standing in the car the car is moving with constant acceleration ‘a’ directed horizontally. Other end of the string is pulled with constant acceleration ‘a’ (relative to car) vertically. We need to find the tension in the string if the θ is constant.


The force on the bob will be in the opposite direction of the motion of the car and also a tension in the string is present.


The forces on the bob of mass m is given by,


It can be seen in the figure that in the y’-y’ direction,


 






The tension in the string is equal to T = m√ a2 + g2 + ma. The correct answer for this problem is option D.


 
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Community Answer
A bob is hanging over a pulley inside a car through a string. The seco...
First we see free body diagram as given in answer
now
we know that। hypotenuse =√ perpendicular^2 + base^2

= √(mg)^2 + (ma)^2
= m √g^2 + a^2

this value will be act as downword force due to gravity

now according to Newtons law of string

T - mg = ma

or T - m√g^2 + a^2 = ma

or T = m√g^2 + a^2 + ma
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A bob is hanging over a pulley inside a car through a string. The second end of the string is in the hand of a person standing in the car. The car is moving with constant accelerationadirected horizontally as shown in figure. Other end of the string is pulled with constant accelerationavertically downward. The tension in the string is equal to :a)b)c)d)Correct answer is option 'D'. Can you explain this answer?
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