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When a certain metallic surface is illuminated with monochromatic light of wavelength λ, the stopping potential for photoelectric current is 3V0 and when the same surface is illuminated with light of wavelength 2λ, the stopping potential is V0. The threshold wavelength of this surface for photoelectric effect is Kλ. Calculate the value of K.
Correct answer is '4'. Can you explain this answer?
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Λ, the electrons in the metal absorb energy from the photons of that specific wavelength. This absorption of energy causes the electrons to transition from their ground state to a higher energy state.
Once the electrons are in the excited state, they are not stable and will quickly return to their ground state. In this process, the excess energy that was absorbed is released in the form of photons. The energy of these emitted photons corresponds to the difference in energy between the excited state and the ground state of the electrons.
This phenomenon is known as the photoelectric effect, where light energy is converted into electrical energy. The energy of the emitted electrons can be calculated using the equation:
E = hf
Where E is the energy of the emitted electron, h is Planck's constant, and f is the frequency of the light. Since frequency is inversely proportional to wavelength (f = c/λ, where c is the speed of light), the energy of the emitted electrons can also be expressed as:
E = hc/λ
This equation shows that the energy of the emitted electrons is inversely proportional to the wavelength of the incident light. As the wavelength increases, the energy of the emitted electrons decreases. This relationship is known as the inverse relationship between energy and wavelength.
In summary, when a metallic surface is illuminated with monochromatic light of wavelength λ, the electrons absorb energy from the photons and transition to a higher energy state. They then release this energy as photons when returning to their ground state. The energy of the emitted photons is inversely proportional to the wavelength of the incident light.
Once the electrons are in the excited state, they are not stable and will quickly return to their ground state. In this process, the excess energy that was absorbed is released in the form of photons. The energy of these emitted photons corresponds to the difference in energy between the excited state and the ground state of the electrons.
This phenomenon is known as the photoelectric effect, where light energy is converted into electrical energy. The energy of the emitted electrons can be calculated using the equation:
E = hf
Where E is the energy of the emitted electron, h is Planck's constant, and f is the frequency of the light. Since frequency is inversely proportional to wavelength (f = c/λ, where c is the speed of light), the energy of the emitted electrons can also be expressed as:
E = hc/λ
This equation shows that the energy of the emitted electrons is inversely proportional to the wavelength of the incident light. As the wavelength increases, the energy of the emitted electrons decreases. This relationship is known as the inverse relationship between energy and wavelength.
In summary, when a metallic surface is illuminated with monochromatic light of wavelength λ, the electrons absorb energy from the photons and transition to a higher energy state. They then release this energy as photons when returning to their ground state. The energy of the emitted photons is inversely proportional to the wavelength of the incident light.
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When a certain metallic surface is illuminated with monochromatic light of wavelength λ, the stopping potential for photoelectric current is 3V0and when the same surface is illuminated with light of wavelength 2λ, the stopping potential is V0. The threshold wavelength of this surface for photoelectric effect is Kλ. Calculate the value of K.Correct answer is '4'. Can you explain this answer?
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When a certain metallic surface is illuminated with monochromatic light of wavelength λ, the stopping potential for photoelectric current is 3V0and when the same surface is illuminated with light of wavelength 2λ, the stopping potential is V0. The threshold wavelength of this surface for photoelectric effect is Kλ. Calculate the value of K.Correct answer is '4'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about When a certain metallic surface is illuminated with monochromatic light of wavelength λ, the stopping potential for photoelectric current is 3V0and when the same surface is illuminated with light of wavelength 2λ, the stopping potential is V0. The threshold wavelength of this surface for photoelectric effect is Kλ. Calculate the value of K.Correct answer is '4'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When a certain metallic surface is illuminated with monochromatic light of wavelength λ, the stopping potential for photoelectric current is 3V0and when the same surface is illuminated with light of wavelength 2λ, the stopping potential is V0. The threshold wavelength of this surface for photoelectric effect is Kλ. Calculate the value of K.Correct answer is '4'. Can you explain this answer?.
When a certain metallic surface is illuminated with monochromatic light of wavelength λ, the stopping potential for photoelectric current is 3V0and when the same surface is illuminated with light of wavelength 2λ, the stopping potential is V0. The threshold wavelength of this surface for photoelectric effect is Kλ. Calculate the value of K.Correct answer is '4'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about When a certain metallic surface is illuminated with monochromatic light of wavelength λ, the stopping potential for photoelectric current is 3V0and when the same surface is illuminated with light of wavelength 2λ, the stopping potential is V0. The threshold wavelength of this surface for photoelectric effect is Kλ. Calculate the value of K.Correct answer is '4'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When a certain metallic surface is illuminated with monochromatic light of wavelength λ, the stopping potential for photoelectric current is 3V0and when the same surface is illuminated with light of wavelength 2λ, the stopping potential is V0. The threshold wavelength of this surface for photoelectric effect is Kλ. Calculate the value of K.Correct answer is '4'. Can you explain this answer?.
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When a certain metallic surface is illuminated with monochromatic light of wavelength λ, the stopping potential for photoelectric current is 3V0and when the same surface is illuminated with light of wavelength 2λ, the stopping potential is V0. The threshold wavelength of this surface for photoelectric effect is Kλ. Calculate the value of K.Correct answer is '4'. Can you explain this answer?, a detailed solution for When a certain metallic surface is illuminated with monochromatic light of wavelength λ, the stopping potential for photoelectric current is 3V0and when the same surface is illuminated with light of wavelength 2λ, the stopping potential is V0. The threshold wavelength of this surface for photoelectric effect is Kλ. Calculate the value of K.Correct answer is '4'. Can you explain this answer? has been provided alongside types of When a certain metallic surface is illuminated with monochromatic light of wavelength λ, the stopping potential for photoelectric current is 3V0and when the same surface is illuminated with light of wavelength 2λ, the stopping potential is V0. The threshold wavelength of this surface for photoelectric effect is Kλ. Calculate the value of K.Correct answer is '4'. Can you explain this answer? theory, EduRev gives you an
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