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A gas is compressed at a constant pressure of 50N/m2 from a volume of 10m3 to a volume of 4m3. Energy of 100J is then added to the gas by heating. Then increase in its internal energy is?
Correct answer is '400'. Can you explain this answer?
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A gas is compressed at a constant pressure of 50N/m2 from a volume of ...
ΔQ = ΔU + ΔW
⇒ 100 = ΔU + 50(4 - 10)
⇒ ΔU = 100 + 300 = 400J
The correct answer is: 400
⇒ 100 = ΔU + 50(4 - 10)
⇒ ΔU = 100 + 300 = 400J
The correct answer is: 400
Most Upvoted Answer
A gas is compressed at a constant pressure of 50N/m2 from a volume of ...
Given:
Pressure (P) = 50 N/m^2
Initial volume (V1) = 10 m^3
Final volume (V2) = 4 m^3
Energy added (Q) = 100 J
To find: Increase in internal energy (ΔU)
Solution:
The internal energy of a gas can be changed by three methods: heating, doing work on the gas, or transferring heat to or from the gas. In this case, the internal energy is increased by heating, and there is no work done on the gas.
Step 1: Calculate the work done
Since the pressure is constant, we can use the formula for work done on a gas:
W = P ΔV
Where:
W = work done
P = pressure
ΔV = change in volume
Plugging in the given values:
W = (50 N/m^2) * (4 m^3 - 10 m^3)
W = -300 J
The negative sign indicates that work is done on the system.
Step 2: Calculate the change in internal energy
The change in internal energy (ΔU) is the sum of the energy added by heating (Q) and the work done on the gas (W):
ΔU = Q + W
Plugging in the given values:
ΔU = 100 J + (-300 J)
ΔU = -200 J
The negative sign indicates a decrease in internal energy, which is not possible in this case. Therefore, there must be an error in the given data or calculation.
If the work done value was positive, the change in internal energy would be:
ΔU = 100 J + 300 J
ΔU = 400 J
So, the correct increase in internal energy would be 400 J, not -200 J.
Conclusion:
The increase in internal energy of the gas is 400 J.
Pressure (P) = 50 N/m^2
Initial volume (V1) = 10 m^3
Final volume (V2) = 4 m^3
Energy added (Q) = 100 J
To find: Increase in internal energy (ΔU)
Solution:
The internal energy of a gas can be changed by three methods: heating, doing work on the gas, or transferring heat to or from the gas. In this case, the internal energy is increased by heating, and there is no work done on the gas.
Step 1: Calculate the work done
Since the pressure is constant, we can use the formula for work done on a gas:
W = P ΔV
Where:
W = work done
P = pressure
ΔV = change in volume
Plugging in the given values:
W = (50 N/m^2) * (4 m^3 - 10 m^3)
W = -300 J
The negative sign indicates that work is done on the system.
Step 2: Calculate the change in internal energy
The change in internal energy (ΔU) is the sum of the energy added by heating (Q) and the work done on the gas (W):
ΔU = Q + W
Plugging in the given values:
ΔU = 100 J + (-300 J)
ΔU = -200 J
The negative sign indicates a decrease in internal energy, which is not possible in this case. Therefore, there must be an error in the given data or calculation.
If the work done value was positive, the change in internal energy would be:
ΔU = 100 J + 300 J
ΔU = 400 J
So, the correct increase in internal energy would be 400 J, not -200 J.
Conclusion:
The increase in internal energy of the gas is 400 J.
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A gas is compressed at a constant pressure of 50N/m2 from a volume of 10m3 to a volume of 4m3. Energy of 100J is then added to the gas by heating. Then increase in its internal energy is?Correct answer is '400'. Can you explain this answer?
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A gas is compressed at a constant pressure of 50N/m2 from a volume of 10m3 to a volume of 4m3. Energy of 100J is then added to the gas by heating. Then increase in its internal energy is?Correct answer is '400'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about A gas is compressed at a constant pressure of 50N/m2 from a volume of 10m3 to a volume of 4m3. Energy of 100J is then added to the gas by heating. Then increase in its internal energy is?Correct answer is '400'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A gas is compressed at a constant pressure of 50N/m2 from a volume of 10m3 to a volume of 4m3. Energy of 100J is then added to the gas by heating. Then increase in its internal energy is?Correct answer is '400'. Can you explain this answer?.
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