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If CV = 4.96 cal/mole-K, then increase in internal energy when temperature of 2moles of this gas is increased from 340K to 342K (in cal)?
Correct answer is '19.84'. Can you explain this answer?
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If CV = 4.96 cal/mole-K, then increase in internal energy when tempera...
Increase in internal energy
ΔU = μCVΔT
= 2 × 4.96 × (342 – 340)
= 19.84 cal
The correct answer is: 19.84
ΔU = μCVΔT
= 2 × 4.96 × (342 – 340)
= 19.84 cal
The correct answer is: 19.84
Most Upvoted Answer
If CV = 4.96 cal/mole-K, then increase in internal energy when tempera...
Increase in Internal Energy of a Gas
To find the increase in internal energy of a gas, we need to use the equation:
ΔU = nCΔT
Where:
ΔU is the increase in internal energy
n is the number of moles of the gas
C is the molar specific heat capacity of the gas at constant volume (CV)
ΔT is the change in temperature
Given:
CV = 4.96 cal/mole-K
n = 2 moles
ΔT = 342K - 340K = 2K
Substituting the given values into the equation, we have:
ΔU = 2 × 4.96 cal/mole-K × 2K
Calculating this expression, we get:
ΔU = 19.84 cal
Therefore, the increase in internal energy when the temperature of 2 moles of this gas is increased from 340K to 342K is 19.84 cal.
Explanation:
The increase in internal energy of a gas can be calculated using the equation ΔU = nCΔT, where ΔU is the increase in internal energy, n is the number of moles of the gas, C is the molar specific heat capacity of the gas at constant volume (CV), and ΔT is the change in temperature.
In this question, we are given the molar specific heat capacity at constant volume (CV) of the gas as 4.96 cal/mole-K. We are also given that the temperature of 2 moles of the gas is increased from 340K to 342K.
To find the increase in internal energy, we substitute the given values into the equation:
ΔU = 2 × 4.96 cal/mole-K × 2K
By simplifying this expression, we get:
ΔU = 19.84 cal
Therefore, the increase in internal energy when the temperature of 2 moles of this gas is increased from 340K to 342K is 19.84 cal.
To find the increase in internal energy of a gas, we need to use the equation:
ΔU = nCΔT
Where:
ΔU is the increase in internal energy
n is the number of moles of the gas
C is the molar specific heat capacity of the gas at constant volume (CV)
ΔT is the change in temperature
Given:
CV = 4.96 cal/mole-K
n = 2 moles
ΔT = 342K - 340K = 2K
Substituting the given values into the equation, we have:
ΔU = 2 × 4.96 cal/mole-K × 2K
Calculating this expression, we get:
ΔU = 19.84 cal
Therefore, the increase in internal energy when the temperature of 2 moles of this gas is increased from 340K to 342K is 19.84 cal.
Explanation:
The increase in internal energy of a gas can be calculated using the equation ΔU = nCΔT, where ΔU is the increase in internal energy, n is the number of moles of the gas, C is the molar specific heat capacity of the gas at constant volume (CV), and ΔT is the change in temperature.
In this question, we are given the molar specific heat capacity at constant volume (CV) of the gas as 4.96 cal/mole-K. We are also given that the temperature of 2 moles of the gas is increased from 340K to 342K.
To find the increase in internal energy, we substitute the given values into the equation:
ΔU = 2 × 4.96 cal/mole-K × 2K
By simplifying this expression, we get:
ΔU = 19.84 cal
Therefore, the increase in internal energy when the temperature of 2 moles of this gas is increased from 340K to 342K is 19.84 cal.
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If CV = 4.96 cal/mole-K, then increase in internal energy when temperature of 2moles of this gas is increased from 340K to 342K (in cal)?Correct answer is '19.84'. Can you explain this answer?
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If CV = 4.96 cal/mole-K, then increase in internal energy when temperature of 2moles of this gas is increased from 340K to 342K (in cal)?Correct answer is '19.84'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about If CV = 4.96 cal/mole-K, then increase in internal energy when temperature of 2moles of this gas is increased from 340K to 342K (in cal)?Correct answer is '19.84'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If CV = 4.96 cal/mole-K, then increase in internal energy when temperature of 2moles of this gas is increased from 340K to 342K (in cal)?Correct answer is '19.84'. Can you explain this answer?.
If CV = 4.96 cal/mole-K, then increase in internal energy when temperature of 2moles of this gas is increased from 340K to 342K (in cal)?Correct answer is '19.84'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about If CV = 4.96 cal/mole-K, then increase in internal energy when temperature of 2moles of this gas is increased from 340K to 342K (in cal)?Correct answer is '19.84'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If CV = 4.96 cal/mole-K, then increase in internal energy when temperature of 2moles of this gas is increased from 340K to 342K (in cal)?Correct answer is '19.84'. Can you explain this answer?.
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