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The area of two similar triangles are 49cm square and 64 cm square. If the difference of the corresponding altitudes is 10cm, then find the leaghts of altitudes?
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The area of two similar triangles are 49cm square and 64 cm square. If...
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The area of two similar triangles are 49cm square and 64 cm square. If...
**Given Information:**

- The area of two similar triangles: 49 cm² and 64 cm²
- The difference of the corresponding altitudes: 10 cm

**Let's Solve the Problem Step-by-Step:**

**Step 1: Understand the Concept of Similar Triangles**

Similar triangles are two triangles that have the same shape but possibly different sizes. The corresponding angles of similar triangles are equal, and the corresponding sides are proportional.

**Step 2: Understand the Relationship between Areas of Similar Triangles**

The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. This can be represented as:

(area of triangle 1) / (area of triangle 2) = (side 1 of triangle 1 / side 1 of triangle 2)²

**Step 3: Set up the Ratio of Areas**

Let's set up the ratio of the areas of the given triangles:

49 cm² / 64 cm² = (side 1 of triangle 1 / side 1 of triangle 2)²

**Step 4: Solve for the Ratio of Sides**

To find the ratio of the sides, we take the square root of the ratio of the areas:

√(49/64) = side 1 of triangle 1 / side 1 of triangle 2

**Step 5: Find the Ratio of the Altitudes**

Since the altitudes of two similar triangles are proportional to their corresponding sides, we can say:

(side 1 of triangle 1 / side 1 of triangle 2) = (altitude 1 of triangle 1 / altitude 1 of triangle 2)

**Step 6: Set up the Equation**

Let's set up the equation using the given difference of the corresponding altitudes:

(side 1 of triangle 1 / side 1 of triangle 2) = (altitude 1 of triangle 1 - altitude 1 of triangle 2) / altitude 1 of triangle 2

**Step 7: Substitute the Values**

Substituting the values we found earlier:

√(49/64) = (altitude 1 of triangle 1 - altitude 1 of triangle 2) / altitude 1 of triangle 2

**Step 8: Solve for the Altitudes**

Let's solve the equation for the altitudes:

√(49/64) = (altitude 1 of triangle 1 - altitude 1 of triangle 2) / altitude 1 of triangle 2

√(49/64) * altitude 1 of triangle 2 = altitude 1 of triangle 1 - altitude 1 of triangle 2

√(49/64) * altitude 1 of triangle 2 + altitude 1 of triangle 2 = altitude 1 of triangle 1

Simplifying further:

(√49 * altitude 1 of triangle 2 + 8 * altitude 1 of triangle 2) / 8 = altitude 1 of triangle 1

(7 * altitude 1 of triangle 2 + 8 * altitude 1 of triangle 2) / 8 = altitude 1 of triangle 1

15 * altitude 1 of triangle 2 / 8 = altitude 1 of triangle 1

15 * altitude 1 of triangle 2 = 8 * altitude 1 of triangle
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The area of two similar triangles are 49cm square and 64 cm square. If the difference of the corresponding altitudes is 10cm, then find the leaghts of altitudes?
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The area of two similar triangles are 49cm square and 64 cm square. If the difference of the corresponding altitudes is 10cm, then find the leaghts of altitudes? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about The area of two similar triangles are 49cm square and 64 cm square. If the difference of the corresponding altitudes is 10cm, then find the leaghts of altitudes? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The area of two similar triangles are 49cm square and 64 cm square. If the difference of the corresponding altitudes is 10cm, then find the leaghts of altitudes?.
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