1 mole of ideal monoatomic gas at 27andordm;C expands pressure of 1.5 atm from a volume of 4dm3 to 16dm3.Select one or more:a)b)c)d)Correct answer is option 'A,D'. Can you explain this answer?

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1 mole of ideal monoatomic gas at 27ºC expands pressure of 1.5 atm from a volume of 4dm³ to 16dm³.
Select one or more:

Correct answer is option 'A,D'. Can you explain this answer?

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1 mole of ideal monoatomic gas at 27ºC expands pressure of 1.5 at...

Since processes is adiabatic q = 0.
As the gas expands against constant external processes

= –1.5(16–4) = –18atm-dm³
ΔU = Q + W = 0 + (–18) = –18atm-dm³
The correct answers are: W = –18atm – dm³ , ΔU = –18atm – dm³

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1 mole of ideal monoatomic gas at 27ºC expands pressure of 1.5 atm from a volume of 4dm3 to 16dm3.Select one or more:a)b)c)d)Correct answer is option 'A,D'. Can you explain this answer?

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