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1 mole of ideal monoatomic gas at 27ºC expands under adiabatic conditions at a pressure of 1.5 atm from a volume of 4dm3 to 16dm3.
Select one or more:
Select one or more:
- a)
- b)
- c)
- d)
Correct answer is option 'A,D'. Can you explain this answer?
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1 mole of ideal monoatomic gas at 27ºC expands under adiabatic co...
Since processes is adiabatic q = 0.
As the gas expands against constant external processes
= –1.5(16–4) = –18atm-dm3
ΔU = Q + W = 0 + (–18) = –18atm-dm3
The correct answers are: W = –18atm – dm3 , ΔU = –18atm – dm3
As the gas expands against constant external processes
= –1.5(16–4) = –18atm-dm3
ΔU = Q + W = 0 + (–18) = –18atm-dm3
The correct answers are: W = –18atm – dm3 , ΔU = –18atm – dm3
Most Upvoted Answer
1 mole of ideal monoatomic gas at 27ºC expands under adiabatic co...
Since processes is adiabatic q = 0.
As the gas expands against constant external processes
= –1.5(16–4) = –18atm-dm3
ΔU = Q + W = 0 + (–18) = –18atm-dm3
The correct answers are: W = –18atm – dm3 , ΔU = –18atm – dm3
As the gas expands against constant external processes
= –1.5(16–4) = –18atm-dm3
ΔU = Q + W = 0 + (–18) = –18atm-dm3
The correct answers are: W = –18atm – dm3 , ΔU = –18atm – dm3
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1 mole of ideal monoatomic gas at 27ºC expands under adiabatic conditions at a pressure of 1.5 atm from a volume of 4dm3 to 16dm3.Select one or more:a)b)c)d)Correct answer is option 'A,D'. Can you explain this answer?
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