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Calculate the diffusion constant for the holes when the mobility of the holes is 400cm2/V-s and temperature is 300K?
- a)1.035m m2/s
- b)0.035m m2/s
- c)1.5m m2/s
- d)1.9m m2/s
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
Calculate the diffusion constant for the holes when the mobility of th...
: Dp=VT*μn
= (1.38*10-23*300*400*10-2)/ (1.6*10-19)
= 1.035m m2/s.
= (1.38*10-23*300*400*10-2)/ (1.6*10-19)
= 1.035m m2/s.
Most Upvoted Answer
Calculate the diffusion constant for the holes when the mobility of th...
To calculate the diffusion constant for the holes, we can use the Einstein relation, which relates the diffusion constant to the mobility and thermal voltage. The equation is given as:
D = μ * k * T
where D is the diffusion constant, μ is the mobility, k is the Boltzmann constant, and T is the temperature in Kelvin.
Given that the mobility of the holes is 400 cm2/V-s and the temperature is 300K, we can substitute these values into the equation to calculate the diffusion constant.
- Given:
- Mobility of the holes (μ) = 400 cm2/V-s
- Temperature (T) = 300K
- Calculation:
- Boltzmann constant (k) = 1.38 * 10^-23 J/K (or 8.617 * 10^-5 eV/K)
- Convert mobility from cm2/V-s to m2/s:
- 1 cm2 = 10^-4 m2
- Therefore, mobility (μ) = 400 * 10^-4 m2/V-s = 4 * 10^-2 m2/V-s
- Plug the values into the equation:
- D = μ * k * T
- D = (4 * 10^-2 m2/V-s) * (8.617 * 10^-5 eV/K) * (300K)
- Convert eV to J:
- 1 eV = 1.602 * 10^-19 J
- Therefore, (8.617 * 10^-5 eV/K) = (8.617 * 10^-5 * 1.602 * 10^-19 J/K) = 1.38 * 10^-23 J/K
- Substitute the values and calculate:
- D = (4 * 10^-2 m2/V-s) * (1.38 * 10^-23 J/K) * (300K)
- D = 1.656 * 10^-21 m2/s
- Convert the result to mm2/s:
- 1 m2 = 10^6 mm2
- Therefore, D = 1.656 * 10^-21 m2/s = 1.656 * 10^-15 mm2/s
Therefore, the diffusion constant for the holes is approximately 1.656 * 10^-15 mm2/s, which is closest to option 'A' (1.035 mm2/s).
D = μ * k * T
where D is the diffusion constant, μ is the mobility, k is the Boltzmann constant, and T is the temperature in Kelvin.
Given that the mobility of the holes is 400 cm2/V-s and the temperature is 300K, we can substitute these values into the equation to calculate the diffusion constant.
- Given:
- Mobility of the holes (μ) = 400 cm2/V-s
- Temperature (T) = 300K
- Calculation:
- Boltzmann constant (k) = 1.38 * 10^-23 J/K (or 8.617 * 10^-5 eV/K)
- Convert mobility from cm2/V-s to m2/s:
- 1 cm2 = 10^-4 m2
- Therefore, mobility (μ) = 400 * 10^-4 m2/V-s = 4 * 10^-2 m2/V-s
- Plug the values into the equation:
- D = μ * k * T
- D = (4 * 10^-2 m2/V-s) * (8.617 * 10^-5 eV/K) * (300K)
- Convert eV to J:
- 1 eV = 1.602 * 10^-19 J
- Therefore, (8.617 * 10^-5 eV/K) = (8.617 * 10^-5 * 1.602 * 10^-19 J/K) = 1.38 * 10^-23 J/K
- Substitute the values and calculate:
- D = (4 * 10^-2 m2/V-s) * (1.38 * 10^-23 J/K) * (300K)
- D = 1.656 * 10^-21 m2/s
- Convert the result to mm2/s:
- 1 m2 = 10^6 mm2
- Therefore, D = 1.656 * 10^-21 m2/s = 1.656 * 10^-15 mm2/s
Therefore, the diffusion constant for the holes is approximately 1.656 * 10^-15 mm2/s, which is closest to option 'A' (1.035 mm2/s).
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Calculate the diffusion constant for the holes when the mobility of the holes is 400cm2/V-s and temperature is 300K?a)1.035m m2/sb)0.035m m2/sc)1.5m m2/sd)1.9m m2/sCorrect answer is option 'A'. Can you explain this answer?
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