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A person driving at the speed of 45 km/h reaches office 1 minute early while she reaches 3 minutes late if driving at 40 km/hr. What is the distance (in km) that she is covering?
  • a)
    30
  • b)
    24
  • c)
    32
  • d)
    28
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A person driving at the speed of 45 km/h reaches office 1 minute early...
Difference in time taken = 4min = 1/15hr
Let the total distance covered by person be K m.
Then,
⇒ K/40 – K/45 = 1/15
⇒ 5K = 120
⇒ K = 24 km
∴ Distance covered by person is 24 km.
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Most Upvoted Answer
A person driving at the speed of 45 km/h reaches office 1 minute early...
Given information:
- Speed 1: 45 km/h, arrives 1 minute early
- Speed 2: 40 km/h, arrives 3 minutes late

Let's calculate the distance:

Step 1: Calculate the time taken to cover the distance at each speed
Let the distance be 'd' km
Time taken at 45 km/h = d/45 hours
Time taken at 40 km/h = d/40 hours

Step 2: Form equations using the given information
Given: Time taken at 45 km/h = Time taken at 40 km/h + 4 minutes
d/45 = d/40 + 1/15
Given: Time taken at 45 km/h = Time taken at 40 km/h - 6 minutes
d/45 = d/40 - 1/20

Step 3: Solve the equations to find the distance
Solving the equations:
d/45 = d/40 + 1/15
40d = 45d + 6
5d = 6
d = 6/5 = 1.2 km
Therefore, the distance covered is 1.2 km, which is equivalent to 24 km (since 1 km = 1000 m)
Thus, the correct answer is option B. 24.
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A person driving at the speed of 45 km/h reaches office 1 minute early while she reaches 3 minutes late if driving at 40 km/hr. What is the distance (in km) that she is covering?a)30b)24c)32d)28Correct answer is option 'B'. Can you explain this answer?
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