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The magnetic field strength required to excite an isolated proton to its higher spin state with an electromagnetic radiation of 300 MHz is __________ Tesla (T). (Round off to two decimal places)
[Magnetogyric ratio of proton is 26.75 x 107 rad T–1 s–1]
[Magnetogyric ratio of proton is 26.75 x 107 rad T–1 s–1]
Correct answer is between '7.00,7.10'. Can you explain this answer?
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The formula to calculate the magnetic field strength required is:
B = hf / (γp * 2π)
Where:
- B is the magnetic field strength
- h is Planck's constant (6.626 x 10^-34 J s)
- f is the frequency of the electromagnetic radiation (300 MHz = 300 x 10^6 Hz)
- γp is the magnetogyric ratio of the proton (26.75 x 10^7 rad T^-1)
Substituting the values:
B = (6.626 x 10^-34 J s * 300 x 10^6 Hz) / (26.75 x 10^7 rad T^-1 * 2π)
B = 0.000025 T
Rounding off to two decimal places, the magnetic field strength required is 0.00 T.
The formula to calculate the magnetic field strength required is:
B = hf / (γp * 2π)
Where:
- B is the magnetic field strength
- h is Planck's constant (6.626 x 10^-34 J s)
- f is the frequency of the electromagnetic radiation (300 MHz = 300 x 10^6 Hz)
- γp is the magnetogyric ratio of the proton (26.75 x 10^7 rad T^-1)
Substituting the values:
B = (6.626 x 10^-34 J s * 300 x 10^6 Hz) / (26.75 x 10^7 rad T^-1 * 2π)
B = 0.000025 T
Rounding off to two decimal places, the magnetic field strength required is 0.00 T.
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