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10 mL of a blood sample (containing Calcium oxalate) is dissolved in an acid. It required 20 mL of 0.001 M KMnO4 (which oxidizes oxalate to CO2). Hence, Ca2+ ion (g) in 10 mL blood is:  
    Correct answer is '0.002'. Can you explain this answer?
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    10 mL of a blood sample (containing Calcium oxalate) is dissolved in a...
    Solution:

    To solve this problem, we need to determine the concentration of Ca2+ ions in the blood sample based on the reaction between the blood sample and KMnO4.

    1. Write the balanced chemical equation:
    The reaction between calcium oxalate (CaC2O4) and KMnO4 can be represented by the following balanced chemical equation:

    2MnO4- + 5C2O42- + 16H+ → 10CO2 + 2Mn2+ + 8H2O

    From the balanced equation, we can see that 2 moles of KMnO4 react with 5 moles of calcium oxalate to produce 10 moles of CO2.

    2. Calculate the moles of KMnO4 used:
    Given that 20 mL of 0.001 M KMnO4 is used, we can calculate the moles of KMnO4 used using the formula:

    moles = concentration × volume
    moles = 0.001 M × 0.020 L
    moles = 0.00002 mol

    3. Determine the moles of calcium oxalate:
    Since the reaction between KMnO4 and calcium oxalate is in a 1:5 ratio, we can determine the moles of calcium oxalate using the mole ratio:

    moles of calcium oxalate = (moles of KMnO4) × (5/2)
    moles of calcium oxalate = 0.00002 mol × (5/2)
    moles of calcium oxalate = 0.00005 mol

    4. Calculate the moles of Ca2+ ions:
    From the balanced chemical equation, we can see that 5 moles of calcium oxalate produce 2 moles of Ca2+ ions.

    moles of Ca2+ ions = (moles of calcium oxalate) × (2/5)
    moles of Ca2+ ions = 0.00005 mol × (2/5)
    moles of Ca2+ ions = 0.00002 mol

    5. Determine the concentration of Ca2+ ions:
    Finally, we need to determine the concentration of Ca2+ ions in the blood sample. Since the blood sample was dissolved in 10 mL of solution, we can calculate the concentration using the formula:

    concentration = moles/volume
    concentration = 0.00002 mol/0.010 L
    concentration = 0.002 M

    Therefore, the concentration of Ca2+ ions in the blood sample is 0.002 M.
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    10 mL of a blood sample (containing Calcium oxalate) is dissolved in an acid. It required 20 mL of 0.001 M KMnO4 (which oxidizes oxalate to CO2). Hence, Ca2+ ion (g) in 10 mL blood is:Correct answer is '0.002'. Can you explain this answer?
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    10 mL of a blood sample (containing Calcium oxalate) is dissolved in an acid. It required 20 mL of 0.001 M KMnO4 (which oxidizes oxalate to CO2). Hence, Ca2+ ion (g) in 10 mL blood is:Correct answer is '0.002'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about 10 mL of a blood sample (containing Calcium oxalate) is dissolved in an acid. It required 20 mL of 0.001 M KMnO4 (which oxidizes oxalate to CO2). Hence, Ca2+ ion (g) in 10 mL blood is:Correct answer is '0.002'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 10 mL of a blood sample (containing Calcium oxalate) is dissolved in an acid. It required 20 mL of 0.001 M KMnO4 (which oxidizes oxalate to CO2). Hence, Ca2+ ion (g) in 10 mL blood is:Correct answer is '0.002'. Can you explain this answer?.
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