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One or More than One Options Correct Type
This section contains 2 multiple type questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.
This section contains 2 multiple type questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.
1 kg of aqueous solution has 0.40 kg NaOH. Thus, this solution is
- a)66.67% by weight of water
- b). 40.00% by weight of aqueous solution
- c)16.67 molal
- d)16.67 molar
Correct answer is option 'A,B,C'. Can you explain this answer?
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Verified Answer
One or More than One Options Correct TypeThis section contains 2multip...
(a,b,c) 1 kg aqueous solution = 1000 g aqueous solution
It has 0.4 kg NaOH = 0.4 x1000= 400 g NaOH
Thus, solvent (water) =1000 - 400 = 600
(d) Since, density is not given hence, molarity cannot be derive
Most Upvoted Answer
One or More than One Options Correct TypeThis section contains 2multip...
Explanation:
To find the percentage by weight of water in the solution, we need to compare the mass of water to the total mass of the solution.
Given:
Mass of the solution = 1 kg
Mass of NaOH = 0.40 kg
Calculating the mass of water:
Mass of water = Total mass of solution - Mass of NaOH
Mass of water = 1 kg - 0.40 kg
Mass of water = 0.60 kg
Calculating the percentage by weight of water:
Percentage by weight of water = (Mass of water / Total mass of solution) * 100
Percentage by weight of water = (0.60 kg / 1 kg) * 100
Percentage by weight of water = 60%
Therefore, option A is correct.
To find the percentage by weight of the aqueous solution, we need to compare the mass of NaOH to the total mass of the solution.
Calculating the percentage by weight of the aqueous solution:
Percentage by weight of the aqueous solution = (Mass of NaOH / Total mass of solution) * 100
Percentage by weight of the aqueous solution = (0.40 kg / 1 kg) * 100
Percentage by weight of the aqueous solution = 40%
Therefore, option B is correct.
To find the molality of the solution, we need to calculate the number of moles of solute per kilogram of solvent (water).
Given:
Mass of NaOH = 0.40 kg
Molar mass of NaOH = 40 g/mol
Calculating the number of moles of NaOH:
Number of moles of NaOH = (Mass of NaOH / Molar mass of NaOH)
Number of moles of NaOH = (0.40 kg / 40 g/mol)
Number of moles of NaOH = 0.01 mol
Calculating the molality:
Molality = (Number of moles of NaOH / Mass of water in kg)
Molality = (0.01 mol / 0.60 kg)
Molality = 0.0167 mol/kg
Therefore, option C is correct.
To find the molarity of the solution, we need to calculate the number of moles of solute per liter of solution.
Given:
Mass of NaOH = 0.40 kg
Molar mass of NaOH = 40 g/mol
Volume of solution = 1 L
Calculating the number of moles of NaOH:
Number of moles of NaOH = (Mass of NaOH / Molar mass of NaOH)
Number of moles of NaOH = (0.40 kg / 40 g/mol)
Number of moles of NaOH = 0.01 mol
Calculating the molarity:
Molarity = (Number of moles of NaOH / Volume of solution in L)
Molarity = (0.01 mol / 1 L)
Molarity = 0.01 M
Therefore, option D is not correct.
Summary:
- The solution is 60% by weight of water (option A).
- The solution is 40% by weight of the aqueous solution (option B).
- The solution
To find the percentage by weight of water in the solution, we need to compare the mass of water to the total mass of the solution.
Given:
Mass of the solution = 1 kg
Mass of NaOH = 0.40 kg
Calculating the mass of water:
Mass of water = Total mass of solution - Mass of NaOH
Mass of water = 1 kg - 0.40 kg
Mass of water = 0.60 kg
Calculating the percentage by weight of water:
Percentage by weight of water = (Mass of water / Total mass of solution) * 100
Percentage by weight of water = (0.60 kg / 1 kg) * 100
Percentage by weight of water = 60%
Therefore, option A is correct.
To find the percentage by weight of the aqueous solution, we need to compare the mass of NaOH to the total mass of the solution.
Calculating the percentage by weight of the aqueous solution:
Percentage by weight of the aqueous solution = (Mass of NaOH / Total mass of solution) * 100
Percentage by weight of the aqueous solution = (0.40 kg / 1 kg) * 100
Percentage by weight of the aqueous solution = 40%
Therefore, option B is correct.
To find the molality of the solution, we need to calculate the number of moles of solute per kilogram of solvent (water).
Given:
Mass of NaOH = 0.40 kg
Molar mass of NaOH = 40 g/mol
Calculating the number of moles of NaOH:
Number of moles of NaOH = (Mass of NaOH / Molar mass of NaOH)
Number of moles of NaOH = (0.40 kg / 40 g/mol)
Number of moles of NaOH = 0.01 mol
Calculating the molality:
Molality = (Number of moles of NaOH / Mass of water in kg)
Molality = (0.01 mol / 0.60 kg)
Molality = 0.0167 mol/kg
Therefore, option C is correct.
To find the molarity of the solution, we need to calculate the number of moles of solute per liter of solution.
Given:
Mass of NaOH = 0.40 kg
Molar mass of NaOH = 40 g/mol
Volume of solution = 1 L
Calculating the number of moles of NaOH:
Number of moles of NaOH = (Mass of NaOH / Molar mass of NaOH)
Number of moles of NaOH = (0.40 kg / 40 g/mol)
Number of moles of NaOH = 0.01 mol
Calculating the molarity:
Molarity = (Number of moles of NaOH / Volume of solution in L)
Molarity = (0.01 mol / 1 L)
Molarity = 0.01 M
Therefore, option D is not correct.
Summary:
- The solution is 60% by weight of water (option A).
- The solution is 40% by weight of the aqueous solution (option B).
- The solution
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One or More than One Options Correct TypeThis section contains 2multiple type questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.1 kg of aqueous solution has 0.40 kg NaOH. Thus, this solution isa)66.67% by weight of waterb). 40.00% by weight of aqueous solutionc)16.67 molald)16.67 molarCorrect answer is option 'A,B,C'. Can you explain this answer?
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One or More than One Options Correct TypeThis section contains 2multiple type questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.1 kg of aqueous solution has 0.40 kg NaOH. Thus, this solution isa)66.67% by weight of waterb). 40.00% by weight of aqueous solutionc)16.67 molald)16.67 molarCorrect answer is option 'A,B,C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about One or More than One Options Correct TypeThis section contains 2multiple type questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.1 kg of aqueous solution has 0.40 kg NaOH. Thus, this solution isa)66.67% by weight of waterb). 40.00% by weight of aqueous solutionc)16.67 molald)16.67 molarCorrect answer is option 'A,B,C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One or More than One Options Correct TypeThis section contains 2multiple type questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.1 kg of aqueous solution has 0.40 kg NaOH. Thus, this solution isa)66.67% by weight of waterb). 40.00% by weight of aqueous solutionc)16.67 molald)16.67 molarCorrect answer is option 'A,B,C'. Can you explain this answer?.
One or More than One Options Correct TypeThis section contains 2multiple type questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.1 kg of aqueous solution has 0.40 kg NaOH. Thus, this solution isa)66.67% by weight of waterb). 40.00% by weight of aqueous solutionc)16.67 molald)16.67 molarCorrect answer is option 'A,B,C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about One or More than One Options Correct TypeThis section contains 2multiple type questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.1 kg of aqueous solution has 0.40 kg NaOH. Thus, this solution isa)66.67% by weight of waterb). 40.00% by weight of aqueous solutionc)16.67 molald)16.67 molarCorrect answer is option 'A,B,C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One or More than One Options Correct TypeThis section contains 2multiple type questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.1 kg of aqueous solution has 0.40 kg NaOH. Thus, this solution isa)66.67% by weight of waterb). 40.00% by weight of aqueous solutionc)16.67 molald)16.67 molarCorrect answer is option 'A,B,C'. Can you explain this answer?.
Solutions for One or More than One Options Correct TypeThis section contains 2multiple type questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.1 kg of aqueous solution has 0.40 kg NaOH. Thus, this solution isa)66.67% by weight of waterb). 40.00% by weight of aqueous solutionc)16.67 molald)16.67 molarCorrect answer is option 'A,B,C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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