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At 180C the mobilities of NH+4 and ClO-4 ions are 6.6 x 10-4 and 5.7 x 10-4 cm2 volt-1s-1 at infinite dilution. The value of equivalent conductance of ammonium perchlorate solution at infinite dilution
- a)1.187 x 10-2Sm2eq-1
- b)2.284 x 10-3 Sm2eq-1
- c)1.87 x 10-5Sm2eq-1
- d)2.09 x 10-6 Sm2eq-1
Correct answer is option 'A'. Can you explain this answer?
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At 180C the mobilities of NH+4 and ClO-4 ions are 6.6 x 10-4 and 5.7 x...
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At 180C the mobilities of NH+4 and ClO-4 ions are 6.6 x 10-4 and 5.7 x...
Given:
- Temperature (T) = 180°C = 453 K
- Mobilities of NH4+ and ClO4- ions at infinite dilution:
- μ(NH4+) = 6.6 x 10^-4 cm^2 V^-1 s^-1
- μ(ClO4-) = 5.7 x 10^-4 cm^2 V^-1 s^-1
To find:
The value of equivalent conductance of ammonium perchlorate (NH4ClO4) solution at infinite dilution.
Explanation:
Step 1: Convert the temperature to Kelvin:
T = 180°C = 453 K
Step 2: Calculate the equivalent conductance (Λ) of NH4+ and ClO4- ions:
The equivalent conductance (Λ) of an ion is given by the equation:
Λ = κ / c
where κ is the specific conductance and c is the concentration of the ion.
At infinite dilution, the specific conductance (κ) is equal to the mobility (μ) multiplied by the molar conductivity at infinite dilution (Λ0):
κ = μ * Λ0
Since we are given the mobilities of NH4+ and ClO4- ions at infinite dilution, we can calculate their equivalent conductances:
Λ(NH4+) = μ(NH4+) * Λ0(NH4+)
Λ(ClO4-) = μ(ClO4-) * Λ0(ClO4-)
Step 3: Calculate the molar conductivity at infinite dilution (Λ0):
The molar conductivity at infinite dilution (Λ0) can be calculated using the Kohlrausch's law of independent migration of ions:
Λ0 = Λ - A * √c
where Λ is the equivalent conductance at a given concentration, A is a constant, and c is the concentration.
At infinite dilution, the concentration (c) approaches zero, so the term A * √c becomes negligible.
Therefore, Λ0 = Λ
Step 4: Calculate the equivalent conductance of the ammonium perchlorate (NH4ClO4) solution:
The equivalent conductance of the ammonium perchlorate (NH4ClO4) solution at infinite dilution can be calculated by adding the equivalent conductances of the NH4+ and ClO4- ions:
Λ(NH4ClO4) = Λ(NH4+) + Λ(ClO4-)
Substituting the values of μ(NH4+), μ(ClO4-), and Λ0 into the equations, we get:
Λ(NH4+) = 6.6 x 10^-4 cm^2 V^-1 s^-1 * Λ0(NH4+)
Λ(ClO4-) = 5.7 x 10^-4 cm^2 V^-1 s^-1 * Λ0(ClO4-)
Λ(NH4ClO4) = Λ(NH4+) + Λ(ClO4-)
Step 5: Calculate the value of Λ0(NH4+) and Λ0(Cl
- Temperature (T) = 180°C = 453 K
- Mobilities of NH4+ and ClO4- ions at infinite dilution:
- μ(NH4+) = 6.6 x 10^-4 cm^2 V^-1 s^-1
- μ(ClO4-) = 5.7 x 10^-4 cm^2 V^-1 s^-1
To find:
The value of equivalent conductance of ammonium perchlorate (NH4ClO4) solution at infinite dilution.
Explanation:
Step 1: Convert the temperature to Kelvin:
T = 180°C = 453 K
Step 2: Calculate the equivalent conductance (Λ) of NH4+ and ClO4- ions:
The equivalent conductance (Λ) of an ion is given by the equation:
Λ = κ / c
where κ is the specific conductance and c is the concentration of the ion.
At infinite dilution, the specific conductance (κ) is equal to the mobility (μ) multiplied by the molar conductivity at infinite dilution (Λ0):
κ = μ * Λ0
Since we are given the mobilities of NH4+ and ClO4- ions at infinite dilution, we can calculate their equivalent conductances:
Λ(NH4+) = μ(NH4+) * Λ0(NH4+)
Λ(ClO4-) = μ(ClO4-) * Λ0(ClO4-)
Step 3: Calculate the molar conductivity at infinite dilution (Λ0):
The molar conductivity at infinite dilution (Λ0) can be calculated using the Kohlrausch's law of independent migration of ions:
Λ0 = Λ - A * √c
where Λ is the equivalent conductance at a given concentration, A is a constant, and c is the concentration.
At infinite dilution, the concentration (c) approaches zero, so the term A * √c becomes negligible.
Therefore, Λ0 = Λ
Step 4: Calculate the equivalent conductance of the ammonium perchlorate (NH4ClO4) solution:
The equivalent conductance of the ammonium perchlorate (NH4ClO4) solution at infinite dilution can be calculated by adding the equivalent conductances of the NH4+ and ClO4- ions:
Λ(NH4ClO4) = Λ(NH4+) + Λ(ClO4-)
Substituting the values of μ(NH4+), μ(ClO4-), and Λ0 into the equations, we get:
Λ(NH4+) = 6.6 x 10^-4 cm^2 V^-1 s^-1 * Λ0(NH4+)
Λ(ClO4-) = 5.7 x 10^-4 cm^2 V^-1 s^-1 * Λ0(ClO4-)
Λ(NH4ClO4) = Λ(NH4+) + Λ(ClO4-)
Step 5: Calculate the value of Λ0(NH4+) and Λ0(Cl
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At 180C the mobilities of NH+4 and ClO-4 ions are 6.6 x 10-4 and 5.7 x 10-4 cm2 volt-1s-1 at infinite dilution. The value of equivalent conductance of ammonium perchlorate solution at infinite dilutiona)1.187 x 10-2Sm2eq-1b)2.284 x 10-3 Sm2eq-1c)1.87 x 10-5Sm2eq-1d)2.09 x 10-6 Sm2eq-1Correct answer is option 'A'. Can you explain this answer?
Question Description
At 180C the mobilities of NH+4 and ClO-4 ions are 6.6 x 10-4 and 5.7 x 10-4 cm2 volt-1s-1 at infinite dilution. The value of equivalent conductance of ammonium perchlorate solution at infinite dilutiona)1.187 x 10-2Sm2eq-1b)2.284 x 10-3 Sm2eq-1c)1.87 x 10-5Sm2eq-1d)2.09 x 10-6 Sm2eq-1Correct answer is option 'A'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about At 180C the mobilities of NH+4 and ClO-4 ions are 6.6 x 10-4 and 5.7 x 10-4 cm2 volt-1s-1 at infinite dilution. The value of equivalent conductance of ammonium perchlorate solution at infinite dilutiona)1.187 x 10-2Sm2eq-1b)2.284 x 10-3 Sm2eq-1c)1.87 x 10-5Sm2eq-1d)2.09 x 10-6 Sm2eq-1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At 180C the mobilities of NH+4 and ClO-4 ions are 6.6 x 10-4 and 5.7 x 10-4 cm2 volt-1s-1 at infinite dilution. The value of equivalent conductance of ammonium perchlorate solution at infinite dilutiona)1.187 x 10-2Sm2eq-1b)2.284 x 10-3 Sm2eq-1c)1.87 x 10-5Sm2eq-1d)2.09 x 10-6 Sm2eq-1Correct answer is option 'A'. Can you explain this answer?.
At 180C the mobilities of NH+4 and ClO-4 ions are 6.6 x 10-4 and 5.7 x 10-4 cm2 volt-1s-1 at infinite dilution. The value of equivalent conductance of ammonium perchlorate solution at infinite dilutiona)1.187 x 10-2Sm2eq-1b)2.284 x 10-3 Sm2eq-1c)1.87 x 10-5Sm2eq-1d)2.09 x 10-6 Sm2eq-1Correct answer is option 'A'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about At 180C the mobilities of NH+4 and ClO-4 ions are 6.6 x 10-4 and 5.7 x 10-4 cm2 volt-1s-1 at infinite dilution. The value of equivalent conductance of ammonium perchlorate solution at infinite dilutiona)1.187 x 10-2Sm2eq-1b)2.284 x 10-3 Sm2eq-1c)1.87 x 10-5Sm2eq-1d)2.09 x 10-6 Sm2eq-1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At 180C the mobilities of NH+4 and ClO-4 ions are 6.6 x 10-4 and 5.7 x 10-4 cm2 volt-1s-1 at infinite dilution. The value of equivalent conductance of ammonium perchlorate solution at infinite dilutiona)1.187 x 10-2Sm2eq-1b)2.284 x 10-3 Sm2eq-1c)1.87 x 10-5Sm2eq-1d)2.09 x 10-6 Sm2eq-1Correct answer is option 'A'. Can you explain this answer?.
Solutions for At 180C the mobilities of NH+4 and ClO-4 ions are 6.6 x 10-4 and 5.7 x 10-4 cm2 volt-1s-1 at infinite dilution. The value of equivalent conductance of ammonium perchlorate solution at infinite dilutiona)1.187 x 10-2Sm2eq-1b)2.284 x 10-3 Sm2eq-1c)1.87 x 10-5Sm2eq-1d)2.09 x 10-6 Sm2eq-1Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
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ample number of questions to practice At 180C the mobilities of NH+4 and ClO-4 ions are 6.6 x 10-4 and 5.7 x 10-4 cm2 volt-1s-1 at infinite dilution. The value of equivalent conductance of ammonium perchlorate solution at infinite dilutiona)1.187 x 10-2Sm2eq-1b)2.284 x 10-3 Sm2eq-1c)1.87 x 10-5Sm2eq-1d)2.09 x 10-6 Sm2eq-1Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice Chemistry tests.
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