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Six identical cards are placed on a table. Each card has number '1' marked on one side and number '2' marked on its other side. All the six cards are placed in such a manner that the number '1' is on the upper side. In one try, exactly four (neither more nor less) cards are turned upside down. In how many Ieast number of tries can the cards be turned upside down such that all the six cards show number '2' on the upper side?
- a)3
- b)5
- c)7
- d)This cannot be achieved
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
Six identical cards are placed on a table. Each card has number '1...
Before trying, the Cards show: 111111
First try (make any 4 cards show 2): 222211 2nd try (take one of those showing 1 and three of those showing two and flip): 211121 3rd try (Flip all the ones): 222222...You got it !
The logic used here is that you should be able to get four 1s somehow – which we achieved in the 2nd try.
The logic used here is that you should be able to get four 1s somehow – which we achieved in the 2nd try.
Most Upvoted Answer
Six identical cards are placed on a table. Each card has number '1...
Solution:
To solve this problem, we need to understand that each card has two sides - one with number 1 and the other with number 2. We want to turn all the cards upside down so that the side with number 2 is facing up.
Let's consider the following cases:
Case 1: We turn over four cards in the same try.
In this case, we have four cards facing down, and we need to turn over all of them to show the number 2. Therefore, we need to flip over the remaining two cards as well.
Total number of tries = 1
Case 2: We turn over three cards in one try and one card in another try.
In the first try, we turn over three cards, leaving three cards facing down. In the second try, we flip over one card, leaving two cards facing down. We need to flip over both the cards, and we can do this in the third try.
Total number of tries = 3
Case 3: We turn over two cards in each of two tries.
In the first try, we turn over two cards, leaving four cards facing down. In the second try, we flip over two more cards, leaving two cards facing down. We need to flip over both the cards, and we can do this in the third try.
Total number of tries = 3
Case 4: We turn over two cards in one try and two cards in another try.
In the first try, we turn over two cards, leaving four cards facing down. In the second try, we flip over two more cards, leaving two cards facing down. We need to flip over both the cards, and we can do this in the third try.
Total number of tries = 3
Therefore, the minimum number of tries required to turn all the cards upside down such that all six cards show number 2 on the upper side is 3.
Answer: A) 3
To solve this problem, we need to understand that each card has two sides - one with number 1 and the other with number 2. We want to turn all the cards upside down so that the side with number 2 is facing up.
Let's consider the following cases:
Case 1: We turn over four cards in the same try.
In this case, we have four cards facing down, and we need to turn over all of them to show the number 2. Therefore, we need to flip over the remaining two cards as well.
Total number of tries = 1
Case 2: We turn over three cards in one try and one card in another try.
In the first try, we turn over three cards, leaving three cards facing down. In the second try, we flip over one card, leaving two cards facing down. We need to flip over both the cards, and we can do this in the third try.
Total number of tries = 3
Case 3: We turn over two cards in each of two tries.
In the first try, we turn over two cards, leaving four cards facing down. In the second try, we flip over two more cards, leaving two cards facing down. We need to flip over both the cards, and we can do this in the third try.
Total number of tries = 3
Case 4: We turn over two cards in one try and two cards in another try.
In the first try, we turn over two cards, leaving four cards facing down. In the second try, we flip over two more cards, leaving two cards facing down. We need to flip over both the cards, and we can do this in the third try.
Total number of tries = 3
Therefore, the minimum number of tries required to turn all the cards upside down such that all six cards show number 2 on the upper side is 3.
Answer: A) 3
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Six identical cards are placed on a table. Each card has number '1...
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Six identical cards are placed on a table. Each card has number '1' marked on one side and number '2' marked on its other side. All the six cards are placed in such a manner that the number '1' is on the upper side. In one try, exactly four (neither more nor less) cards are turned upside down. In how many Ieast number of tries can the cards be turned upside down such that all the six cards show number '2' on the upper side?a)3b)5c)7d)This cannot be achievedCorrect answer is option 'A'. Can you explain this answer?
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Six identical cards are placed on a table. Each card has number '1' marked on one side and number '2' marked on its other side. All the six cards are placed in such a manner that the number '1' is on the upper side. In one try, exactly four (neither more nor less) cards are turned upside down. In how many Ieast number of tries can the cards be turned upside down such that all the six cards show number '2' on the upper side?a)3b)5c)7d)This cannot be achievedCorrect answer is option 'A'. Can you explain this answer? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Six identical cards are placed on a table. Each card has number '1' marked on one side and number '2' marked on its other side. All the six cards are placed in such a manner that the number '1' is on the upper side. In one try, exactly four (neither more nor less) cards are turned upside down. In how many Ieast number of tries can the cards be turned upside down such that all the six cards show number '2' on the upper side?a)3b)5c)7d)This cannot be achievedCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Six identical cards are placed on a table. Each card has number '1' marked on one side and number '2' marked on its other side. All the six cards are placed in such a manner that the number '1' is on the upper side. In one try, exactly four (neither more nor less) cards are turned upside down. In how many Ieast number of tries can the cards be turned upside down such that all the six cards show number '2' on the upper side?a)3b)5c)7d)This cannot be achievedCorrect answer is option 'A'. Can you explain this answer?.
Six identical cards are placed on a table. Each card has number '1' marked on one side and number '2' marked on its other side. All the six cards are placed in such a manner that the number '1' is on the upper side. In one try, exactly four (neither more nor less) cards are turned upside down. In how many Ieast number of tries can the cards be turned upside down such that all the six cards show number '2' on the upper side?a)3b)5c)7d)This cannot be achievedCorrect answer is option 'A'. Can you explain this answer? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Six identical cards are placed on a table. Each card has number '1' marked on one side and number '2' marked on its other side. All the six cards are placed in such a manner that the number '1' is on the upper side. In one try, exactly four (neither more nor less) cards are turned upside down. In how many Ieast number of tries can the cards be turned upside down such that all the six cards show number '2' on the upper side?a)3b)5c)7d)This cannot be achievedCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Six identical cards are placed on a table. Each card has number '1' marked on one side and number '2' marked on its other side. All the six cards are placed in such a manner that the number '1' is on the upper side. In one try, exactly four (neither more nor less) cards are turned upside down. In how many Ieast number of tries can the cards be turned upside down such that all the six cards show number '2' on the upper side?a)3b)5c)7d)This cannot be achievedCorrect answer is option 'A'. Can you explain this answer?.
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ample number of questions to practice Six identical cards are placed on a table. Each card has number '1' marked on one side and number '2' marked on its other side. All the six cards are placed in such a manner that the number '1' is on the upper side. In one try, exactly four (neither more nor less) cards are turned upside down. In how many Ieast number of tries can the cards be turned upside down such that all the six cards show number '2' on the upper side?a)3b)5c)7d)This cannot be achievedCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice UPSC tests.
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