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The dielectric strength of rubber is 30000 V/mm at a frequency of 50 Hz. What is the thickness of insulation required on an electrical conductor at 33 kV to sustain the breakdown?
- a)0.9 cm
- b)0.8 mm
- c)1.0 cm
- d)1.1 mm
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
The dielectric strength of rubber is 30000 V/mm at a frequency of 50 H...
Given that,
Electric field (E) = 30000 V/mm
Breakdown voltage (V) = 33 kV
Most Upvoted Answer
The dielectric strength of rubber is 30000 V/mm at a frequency of 50 H...
Dielectric Strength and Breakdown Voltage
Dielectric strength is a measure of the electrical insulation capability of a material. It represents the maximum electric field that a material can withstand before it breaks down and allows current to flow through it. For insulating materials like rubber, dielectric strength is an important property to consider in electrical applications.
In this case, the dielectric strength of rubber is given as 30,000 V/mm at a frequency of 50 Hz. This means that the rubber insulation can withstand an electric field of 30,000 volts per millimeter before it breaks down.
Calculating the Required Insulation Thickness
To determine the thickness of insulation required on an electrical conductor at 33 kV to sustain the breakdown, we can use the formula:
Insulation thickness (mm) = Voltage (kV) / Electric field strength (V/mm)
Here, the voltage is given as 33 kV. We need to convert this to volts by multiplying it by 1,000 to get 33,000 V. The electric field strength is given as 30,000 V/mm.
Substituting these values into the formula, we get:
Insulation thickness (mm) = 33,000 V / 30,000 V/mm
Simplifying the equation, we find:
Insulation thickness (mm) = 1.1 mm
Therefore, the required insulation thickness on the electrical conductor to sustain the breakdown at 33 kV is 1.1 mm.
Conclusion
In summary, to determine the insulation thickness required on an electrical conductor to sustain the breakdown at a given voltage, we need to know the dielectric strength of the insulating material. By using the formula for insulation thickness calculation and substituting the given values, we can calculate the required thickness. In this case, the correct answer is option D, 1.1 mm.
Dielectric strength is a measure of the electrical insulation capability of a material. It represents the maximum electric field that a material can withstand before it breaks down and allows current to flow through it. For insulating materials like rubber, dielectric strength is an important property to consider in electrical applications.
In this case, the dielectric strength of rubber is given as 30,000 V/mm at a frequency of 50 Hz. This means that the rubber insulation can withstand an electric field of 30,000 volts per millimeter before it breaks down.
Calculating the Required Insulation Thickness
To determine the thickness of insulation required on an electrical conductor at 33 kV to sustain the breakdown, we can use the formula:
Insulation thickness (mm) = Voltage (kV) / Electric field strength (V/mm)
Here, the voltage is given as 33 kV. We need to convert this to volts by multiplying it by 1,000 to get 33,000 V. The electric field strength is given as 30,000 V/mm.
Substituting these values into the formula, we get:
Insulation thickness (mm) = 33,000 V / 30,000 V/mm
Simplifying the equation, we find:
Insulation thickness (mm) = 1.1 mm
Therefore, the required insulation thickness on the electrical conductor to sustain the breakdown at 33 kV is 1.1 mm.
Conclusion
In summary, to determine the insulation thickness required on an electrical conductor to sustain the breakdown at a given voltage, we need to know the dielectric strength of the insulating material. By using the formula for insulation thickness calculation and substituting the given values, we can calculate the required thickness. In this case, the correct answer is option D, 1.1 mm.
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The dielectric strength of rubber is 30000 V/mm at a frequency of 50 Hz. What is the thickness of insulation required on an electrical conductor at 33 kV to sustain the breakdown?a)0.9 cmb)0.8 mmc)1.0 cmd)1.1 mmCorrect answer is option 'D'. Can you explain this answer?
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