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Compute the conductivity when the current density is 12 units and the electric field is 20 units. Also identify the nature of the material.
  • a)
    1.67, dielectric
  • b)
    1.67, conductor
  • c)
    0.6, dielectric
  • d)
    0.6, conductor
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
Compute the conductivity when the current density is 12 units and the ...
Answer: c
Explanation: The current density is the product of conductivity and electric field intensity. J = σE. To get σ, put J = 12 and E = 20. σ = 12/20 = 0.6. Since the conductivity is less than unity, the material is a dielectric.
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Most Upvoted Answer
Compute the conductivity when the current density is 12 units and the ...
To calculate the conductivity, we can use Ohm's law, which states that the current density (J) is equal to the product of the conductivity (σ) and the electric field (E):

J = σ * E

Given that the current density (J) is 12 units and the electric field (E) is 20 units, we can substitute these values into the equation and solve for conductivity (σ).

J = σ * E
12 = σ * 20

Simplifying the equation, we can isolate σ:

σ = 12 / 20
σ = 0.6

Therefore, the conductivity is 0.6 units.

Nature of the Material:
The nature of the material can be determined based on the magnitude of the conductivity. Conductivity is a measure of how well a material conducts electricity. Materials with high conductivity are good conductors, while materials with low conductivity are dielectrics or insulators.

In this case, the conductivity is 0.6 units, which is relatively low. Therefore, the material can be classified as a dielectric. Dielectrics are materials that do not conduct electricity well and are often used as insulators in electrical systems.

Therefore, the correct answer is option C) 0.6, dielectric.
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Compute the conductivity when the current density is 12 units and the electric field is 20 units. Also identify the nature of the material.a)1.67, dielectricb)1.67, conductorc)0.6, dielectricd)0.6, conductorCorrect answer is option 'C'. Can you explain this answer?
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