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A is twice as good a workman as B and is therefore able to finish a piece of work in 30 days less than (B) In how many days they can complete the whole work, working together?
- a)10 days
- b)15 days
- c)20 days
- d)25 days
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A is twice as good a workman as B and is therefore able to finish a pi...
Ratio of efficiency = 2 : 1 (A : B) Ratio of required time =1:2(A:B)⇒x:2x But 2x−x=30 ⇒ x=30 and 2x=60 Now, efficiency of A = 3. 33% And efficiency of B = 1.66% Combined efficiency of A and B together = 5% So, time required by A and B working together to finish the work =100/5=20 days
Most Upvoted Answer
A is twice as good a workman as B and is therefore able to finish a pi...
Given data:
A is twice as good a workman as B
A finishes a piece of work in 30 days less than B
To find:
In how many days they can complete the whole work, working together?
Solution:
Let us assume that the total work is 120 units (LCM of 30 and 60).
Therefore, B can complete 1 unit of work in 60 days and A can complete 2 units of work in 60 days.
Working individually:
A can complete the work in 60/2 = 30 days.
B can complete the work in 60/1 = 60 days.
Working together:
Let us assume that they complete the work in x days when working together.
Therefore, the work done by A in x days = (x/30) units.
And, the work done by B in x days = (x/60) units.
As they are working together, the total work done in x days = (x/30) + (x/60) units.
We know that the total work done is 120 units.
Therefore, (x/30) + (x/60) = 120
Solving the above equation, we get x = 20 days
Hence, they can complete the whole work in 20 days, working together.
Answer: Option C
A is twice as good a workman as B
A finishes a piece of work in 30 days less than B
To find:
In how many days they can complete the whole work, working together?
Solution:
Let us assume that the total work is 120 units (LCM of 30 and 60).
Therefore, B can complete 1 unit of work in 60 days and A can complete 2 units of work in 60 days.
Working individually:
A can complete the work in 60/2 = 30 days.
B can complete the work in 60/1 = 60 days.
Working together:
Let us assume that they complete the work in x days when working together.
Therefore, the work done by A in x days = (x/30) units.
And, the work done by B in x days = (x/60) units.
As they are working together, the total work done in x days = (x/30) + (x/60) units.
We know that the total work done is 120 units.
Therefore, (x/30) + (x/60) = 120
Solving the above equation, we get x = 20 days
Hence, they can complete the whole work in 20 days, working together.
Answer: Option C
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A is twice as good a workman as B and is therefore able to finish a piece of work in 30 days less than (B) In how many days they can complete the whole work, working together?a)10 daysb)15 daysc)20 daysd)25 daysCorrect answer is option 'C'. Can you explain this answer?
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