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A hollow circular shaft has an outer diameter of 100 mm and inner diameter of 50 mm. If the allowable shear stress is 125 MPa, the maximum torque (in kN-m) that the shaft can resist is_______ 
    Correct answer is '23.009'. Can you explain this answer?
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    A hollow circular shaft has an outer diameter of 100 mm and inner diam...

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    A hollow circular shaft has an outer diameter of 100 mm and inner diam...
    Given data:
    Outer diameter, D = 100 mm
    Inner diameter, d = 50 mm
    Allowable shear stress, τ = 125 MPa

    To find: Maximum torque, T

    Assumption:
    The shaft is made up of a homogeneous material and the shear stress is uniform across the section.

    Formula used:
    Polar moment of inertia, J = π/2 (D^4 - d^4)
    Maximum shear stress, τmax = T/J

    Calculation:
    Polar moment of inertia, J = π/2 (D^4 - d^4)
    J = π/2 ((0.1)^4 - (0.05)^4)
    J = 2.287 * 10^-6 m^4

    Maximum shear stress, τmax = T/J
    125 MPa = T/(2.287 * 10^-6 m^4)
    T = 286.75 N-m = 0.28675 kN-m (Answer)

    Therefore, the maximum torque that the shaft can resist is 0.28675 kN-m.

    Note: The given answer is incorrect. The correct answer is 0.28675 kN-m, not 23.009 kN-m.
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    A hollow circular shaft has an outer diameter of 100 mm and inner diameter of 50 mm. If the allowable shear stress is 125 MPa, the maximum torque (in kN-m) that the shaft can resist is_______Correct answer is '23.009'. Can you explain this answer?
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